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igomit [66]
3 years ago
6

Find the greatest common factor of 24 and 76_______________________

Mathematics
2 answers:
hodyreva [135]3 years ago
4 0

Using Euclid's algorithm, divide 76 by 24. The result is 3 r 4. Now, divide 24 by the remainder. That result is 6 r 0. Since the remainder is zero, the divisor (4) is the greatest common factor of 76 and 24.

The GCF of 76 and 24 is 4.

_____

Another way to look at it is to factor the two numbers and see what factors they have in common.

76 = 4·19

24 = 4·6

since 6 an 19 have no common factors, 4 is the greatest common factor of 76 and 24.

Softa [21]3 years ago
4 0

The greatest common factor(GCF) of 24 and 76 is 4.

4 goes into 24 six times.

4 goes into 76 nineteen times.

Which is the highest factor that can go into the both of them.

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Parts being manufactured at a plant are supposed to weigh 65 grams. Suppose the distribution of weights has a Normal distributio
andrew-mc [135]

Answer:

0.64%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 75 grams and a standard deviation of 22 grams.

This means that \mu = 75, \sigma = 22

Sample of 144:

This means that n = 144, s = \frac{22}{\sqrt{144}} = 1.8333

More than 80 or less than 70:

Both are the same distance from the mean, so we find one probability and multiply by 2.

The probability that it is less than 70 is the pvalue of Z when X = 70. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{70 - 75}{1.8333}

Z = -2.73

Z = -2.73 has a pvalue of 0.0032

2*0.0032 = 0.0064.

0.0064*100% = 0.64%

The probability is 0.64%.

3 0
3 years ago
Is 6200 ft greater or less than 1 mile 900 ft
Sphinxa [80]
1 mile is equal to 5280 feet

Add 900 to it:

5280 + 900 = 6180

6180 is less than 6200, so 1 mile and 900 feet is less than 6200 feet.
7 0
3 years ago
Read 2 more answers
According to the census data, in 2014 about 126 million adults in the United States were women, which is about 51.4% of the tota
jeka57 [31]

Answer:

245.1361868

Step-by-step explanation:

126               51.4

___    =        ____             126x100=12600      12600/51.4=245.1361868

 x                  100

6 0
3 years ago
The proof that ΔACB ≅ ΔECD is shown. Given: AE and DB bisect each other at C. Prove: ΔACB ≅ ΔECD What is the missing statement i
GarryVolchara [31]

Answer:

The missing statement is ∠ACB ≅ ∠ECD

Step-by-step explanation:

Given two lines segment AC and BD bisect each other at C.

We have to prove that ΔACB ≅ ΔECD

In triangle ACB and ECD

AC=CE    (Given)

BC=CD   (Given)

Now to prove above two triangles congruent we need one more side or angle

so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles

hence, the missing statement is ∠ACB ≅ ∠ECD


9 0
3 years ago
Read 2 more answers
One lap around a track is one eigth of a mile.a horse ran a distance of 11 laps in 3 minutes and 30 seconds.what is the horses a
pantera1 [17]
Miles earned= ((1÷8)×11)÷1
= 1.375 miles
average speed=total distance/total time
=1.375÷3.5=0.3928 miles/min
5 0
3 years ago
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