Answer: Triangle 2 is congruent to triangle 1 because a translation is a rigid motion
Step-by-step explanation:
Answer:
E and D
Step-by-step explanation:
Answer:
3x-x+2=4 :)
Step-by-step explanation:
Hope this helped! :3
Answer:
Step-by-step explanation:
m (x) = (x+ 5) / (x -1) and n(x) = x - 3.
![m(x) = \dfrac{x+5}{x-1}](https://tex.z-dn.net/?f=m%28x%29%20%3D%20%5Cdfrac%7Bx%2B5%7D%7Bx-1%7D)
Hence
![m(n) = \dfrac{n+5}{n-1}](https://tex.z-dn.net/?f=m%28n%29%20%3D%20%5Cdfrac%7Bn%2B5%7D%7Bn-1%7D)
but n is a function and n = x-3. Now, replace value of n on m (n)
![(m(n))= \dfrac{(x-3)+5}{(x-3)-1}](https://tex.z-dn.net/?f=%28m%28n%29%29%3D%20%5Cdfrac%7B%28x-3%29%2B5%7D%7B%28x-3%29-1%7D)
simplify it
![(m\bullet n)(x) =\dfrac{x+2}{x-4}\\](https://tex.z-dn.net/?f=%28m%5Cbullet%20n%29%28x%29%20%3D%5Cdfrac%7Bx%2B2%7D%7Bx-4%7D%5C%5C)
since (m . n) (x) is a fraction function, its domain will be all x such that the denominator is NOT 0. That is
![x-4\ne 0\rightarrow x\ne 4](https://tex.z-dn.net/?f=x-4%5Cne%200%5Crightarrow%20x%5Cne%204)
among options, only C has the same denominator with ![(m\bullet n)(x)](https://tex.z-dn.net/?f=%28m%5Cbullet%20n%29%28x%29)
Hence their domains are the same.
C is the best one I'm pretty sure it makes the most sense