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AURORKA [14]
4 years ago
10

The reaction below is allowed to come to equilibrium. After equilibrium is reached, the temperature of the container is raised b

y 50ºC. Which statement below describes a change that will be observed as the system returns to an equilibrium state at the new temperature if ΔH is positive?
2 NH3(g) ⇄ N2(g) + 3 H2(g)

a. The concentration of ammonia, NH3, will increase.
b. The concentration of nitrogen gas, N2, will decrease.
c. The rate of the forward reaction will increase.
d. There will be no change; increasing the temperature will not change the position of equilibrium.
Chemistry
1 answer:
strojnjashka [21]4 years ago
3 0

Answer: c. The rate of the forward reaction will increase.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)  \Delta H=+ve

This is a type of Endothermic reaction because heat is absorbed in the reaction.

When the temperature  is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in temperature occurs. As, this is an endothermic reaction, forward reaction will decrease the temperature. Hence, the equilibrium will shift in the right or forward direction.

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Radio waves are ____________ waves.
Elina [12.6K]

Radio waves are electromagnetic waves.

4 0
4 years ago
What is the molarity of a solution that is 26.0% by mass in phosphoric acid, H3PO4, and that has a density of 1.155 g/mL?
steposvetlana [31]

Answer: The molarity of a solution that is 26.0% by mass in phosphoric acid is 3.06 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

n = moles of solute

V_s =volume of solution in ml

Given : 26.0 g of phosphoric acid in 100 g of solution.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{26.0g}{98g/mol}=0.265moles

Volume of solution =\frac{\text {Mass of solution}}{\text {Density of solution}}=\frac{100g}{1.155g/ml}=86.6ml

Molarity=\frac{0.265\times 1000}{86.6ml}=3.06M

Molarity of a solution that is 26.0% by mass in phosphoric acid is 3.06 M

8 0
4 years ago
Consider the model of a sodium atom .Which feature does the model show accurately ?
nignag [31]
It shows that the sodium atom has 11 protons and 12 neutrons, arranged in a ball shape.
8 0
4 years ago
Helppp ! Please :’)
Over [174]

Answer:

\boxed{\sf \lambda \:  = 1.282 \times    {10}^{ 3} nm}

Explanation:

Suppose an electron makes transition from n initial (ni) to n final (nf) then formula for wavelength is given by,

\frac{1}{ \lambda}  = R_H {Z}^{2}  \big(\frac{1}{{n_f^2}}  - \frac{1}{{n_i^2}} \big)

Where,

  • λ is wavelength of photon
  • Rʜ is rydberg constant, the value of Rʜ is

109690 Cm-¹ in <em>Puri Sharma Pathania</em> standard book of physical chemistry &

109737 Cm-¹ according to <em>Wikipedia</em>

  • Z is the atomic number of atom, for hydrogen Z =1,

& according to given data, ni = 5, nf = 3

Solution:

Let's solve for wavelength,

Substituting all the given data in above formula,

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \big(\frac{1}{{3^2}}  - \frac{1}{{5^2}} \big)

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \big(\frac{1}{{9}}  - \frac{1}{{25}} \big)

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \times   \frac{25 - 9}{25 \times 9}

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \times   \frac{16}{225}

\frac{1}{ \lambda}  =   7800.18 \: \: cm ^{ - 1}

\lambda = 1.282 \times  {10}^{ - 4} cm

Now we know that, 1 cm = 10000000 nm,

Converting the wavelength from Cm → Nm

\lambda \:  = 1.282 \times  {10}^{ - 4} \times  {10}^{7}

\lambda \:  = 1.282 \times  {10}^{ - 4 + 7}

\sf \lambda \:  = 1.282 \times    {10}^{ 3} nm

\sf \small Thanks \:  for \:  joining \:  brainly  \: community!

4 0
2 years ago
Why are acids, bases and even some salts commonly used in cleaning applications?
Jet001 [13]

Answer:

Hope this helps :)

Explanation:

In the chemical industry, acids react in neutralization reactions to produce salts. For example, nitric acid reacts with ammonia to produce ammonium nitrate, a fertilizer. Additionally, carboxylic acids can be esterified with alcohols, to produce esters.

Acids are used to remove mineral deposits, rust stains, and hard water deposits. They can remove discoloration from some metals, such as aluminum, brass, bronze, and copper. Some acids are effective both in cleaning and disinfecting surfaces.

4 0
3 years ago
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