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coldgirl [10]
3 years ago
7

What happens if balanced forces are applied to a moving object? A. The object stops moving. B. The object moves faster in the sa

me direction. C. The object moves slower in the same direction. D. The object keeps moving at the same speed and direction.
Physics
1 answer:
Gemiola [76]3 years ago
7 0

Answer:

The object keeps moving at the same speed and direction.

Explanation:

This is because the balanced forces acting on the object cancel out each other since the are in opposite directions, leaving only the original force acting on the object which is causing its motion.To illustrate, let F₁ be the initial force and F₂ and F₃ be the balanced forces. The net force F = F₁ + F₂ + F₃. Since F₂ and F₃ are balanced, F₂ = -F₃ ⇒ F₂ + F₃ = 0.

So,

F = F₁ + F₂ + F₃

  = F₁ + (F₂ + F₃)

  = F₁ + 0

  = F₁

Which is the original force acting on the object. Thus, the object keeps moving at the same speed and direction

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Answer:

Mother

Explanation:

Is this actual question

5 0
3 years ago
An electron, starting from rest and moving with a constant acceleration, travels 2.0 cm in 5.0 ms. What is the magnitude of this
IrinaK [193]
 <span>s=2.7 centimeters = 0.027 meters 
t=3.9 milliseconds = 0.0039 seconds 

s=(1/2)a*t^2 
so 
a=(2.7*2)/(0.0039)^2 
= 355,029.58 m/s^2 

a=355,029.58 m/s^2 = 355.02958 km / s^2</span>
7 0
3 years ago
A 20 cm-long wire carrying a current of 6 A is immersed in a uniform magnetic field of 3 T. If the magnetic field is oriented at
SOVA2 [1]

Answer:

the  magnitude of the force that the wire will experience = 1.8 N

Explanation:

The force on a current carrying wire placed in a magnetic field is :

F = Idl × B

where:

I = current flowing through the wire

dl = length of the wire

B = magnetic field

We can equally say that :

|F| = IdlBsin \theta

where : sin θ is the angle at which the orientation from the magnetic field  to the wire occurs = 30°

Then;

|F| = B\ I \ L \ sin \theta

Given that:

L = 20 cm = 0.2 m

I = 6 A

B = 3 T

θ = 30°

Then:

F = 3 × 6 × 0.2 sin 30°

F = 1.8 N

Therefore, the  magnitude of the force that the wire will experience = 1.8 N

6 0
3 years ago
URGENT <br> Find the total<br> equivalent<br> resistance for the<br> circuit.
Nesterboy [21]

Answer:

20 + 10 = 30 \\ 30and50 in \: parallel \\  =  \frac{50 \times 30}{50 + 30}  \\  =  \frac{1500}{80}  \\ 18.75 \\ 30nd40parallel \\  \frac{30 \times 40}{70}  \\  \frac{1200}{70}  = 17.143 \\ total = 18.75 + 17.143 = 35.893ohm \\ thank \: u

3 0
2 years ago
If all of the forces acting on an object balance so that the net force is zero, then
nadya68 [22]
The answer is (A) the object must be at rest.

When all of the forces acting on an object balance, the net force is zero and hence the object will not move.

Yes, the direction might also change under some special circumstances. 
6 0
3 years ago
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