The horizontal component of the magnetic field is 12.6 μT.
The magnetic influence on moving electric currents, electric charges, and magnetic materials is described by a magnetic field, which is a vector field. When a charge moves through a magnetic field, a force that is perpendicular to both its own velocity and the magnetic field operates on it.
The horizontal component of the Earth's magnetic field is perpendicular to the axis of a circular coil with five turns and a diameter of D = 30.0 cm that is vertically orientated.
A coil current of I = 0.600 A causes a horizontal compass to deflect 45.0° from magnetic north when it is positioned in the coil's center.
Let B be the magnetic field and R be the radius of the circular coil.
Then the horizontal component of the Earth's magnetic field is given as:
B(h) = B(coil) = μ₀ NI / 2R
B(h) = (4π × 10⁻⁷ ) (5)(0.6) / 0.3
B(h) = 12.6 μT
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Answer:
Approximately
, assuming that the gravitational field strength is
.
Explanation:
Let
denote the required angular velocity of this Ferris wheel. Let
denote the mass of a particular passenger on this Ferris wheel.
At the topmost point of the Ferris wheel, there would be at most two forces acting on this passenger:
- Weight of the passenger (downwards),
, and possibly - Normal force
that the Ferris wheel exerts on this passenger (upwards.)
This passenger would feel "weightless" if the normal force on them is
- that is,
.
The net force on this passenger is
. Hence, when
, the net force on this passenger would be equal to
.
Passengers on this Ferris wheel are in a centripetal motion of angular velocity
around a circle of radius
. Thus, the centripetal acceleration of these passengers would be
. The net force on a passenger of mass
would be
.
Notice that
. Solve this equation for
, the angular speed of this Ferris wheel. Since
and
:
.
.
The question is asking for the angular velocity of this Ferris wheel in the unit
, where
. Apply unit conversion:
.
B is the answer you need and i honestly got this question on a middle school test
you must be in different area then me