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erica [24]
4 years ago
7

Write the equation of the parabola that has the vertex at point (1,3) and passes through the point (−1,5).

Mathematics
1 answer:
Andrei [34K]4 years ago
6 0

Answer:

y = \frac{1}{2} x² - x + \frac{7}{2}

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (1, 3 ), thus

y = a(x - 1)² + 3

To find a substitute (- 1, 5) into the equation

5 = a(- 1 - 1)² + 3 ( subtract 3 from both sides )

2 = 4a ( divide both sides by 4 )

a = \frac{1}{2} , thus

y = \frac{1}{2} (x - 1)² + 3 ← expand factor using FOIL

y = \frac{1}{2} (x² - 2x + 1) + 3 ← distribute parenthesis

  = \frac{1}{2} x² - x + \frac{1}{2} + 3

  = \frac{1}{2} x² - x + \frac{7}{2}

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