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3 years ago

How do you graph Y > 6x + 3 ?

Mathematics

2 answers:

Kipish [7]3 years ago

8 0

I hope I helped! Comment if you have any questions :)

erastovalidia [21]3 years ago

8 0

Answer:

The line would start on y=6 and go up three over one and if im correct the line would be dotted and saded upwards

Step-by-step explanation:

N/A

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Look at pic plz help

jasenka [17]

Answer:

Mochi

Step-by-step explanation:

Mochi

Each week theres a increase of 4 in Mochi's weight. So you will add 4 twice to get to the 5th week.

4th week : 17

5th week : 21

Kappa

In 4 weeks Kappa weighed 14, which is less that Mochi at the pace Kappa is going at.

on the 3rd week Kappa weighed 11

and 2nd week Kappa weighed 5

and 1st week Kappa weighed 3

Looking at the graph, we can give a rough estimate on the 5th week it's going to be 16 or 17 either way making Mochi heavier.

8 0

3 years ago

A tourist purchases a car in england and ships it home to the united states. the car sticker advertised that the car's fuel cons

Valentin [98]

<u>Solution-</u>

Fuel consumption rate = 40 miles per UK gallon (As the car is manufactured in UK)

1 UK gallon = 4.5459631 lit

1 US gallon = 3.7853060 lit

$\therefore \frac{1 \ UK \ gallon}{1 \ US \ gallon} = \frac{4.5459631}{3.7853060} = 1.2009499$

$\Rightarrow 1 \ UK \ gallon = 1.2009499 \ US \ gallon$

As the fuel consumption rate = 40 miles per gallon

⇒ You need 1 UK gallon of fuel to go 40 miles

⇒ You need 1.2009499 US gallon of fuel to go 40 miles

Or you can say that, to go 40 miles you need 1.2009499 US gallon of fuel

⇒ To go 1 mile you will need $\frac{1.2009499}{40} = 0.0300237$

⇒ To go 738 miles you will need 0.0300237×738 = 22.1574906 US gallon of fuel

∴ 22.1574906 gallon of fuel is actually required.

∴ But, what she thinks will require is $\frac{738}{40} = 18.45 gallons$ (As she calculated using UK gallons)

6 0

3 years ago

Carl is standing at the top of 35 Ft cliff looking down at a rock for motion in the sea. He estimates the angle of depression is

Liula [17]

The horizontal distance between Carl and the rock at sea is approximately 60.62ft.

Data;

Angle = 30 degree
Opposite = 35
Adjacent = x

<h3>Trigonometric Ratio</h3>

Given the angle of depression from his point to the sea, we can use trigonometric ratio to calculate for the horizontal distance from his location to the bottom of the sea.

SOHCAHTOA

Since we have the value of angle and opposite and we need to calculate the adjacent side of the right-angle triangle, we can use the tangent of the angle to this effect.

$Tan\theta = \frac{opposite}{adjacent} \\tan 30 = \frac{35}{x}\\ x = \frac{35}{tan30}\\ x = 60.62ft$