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2 years ago

A proton moving along the positive x-axis enters a uniform magnetic field which is directed along the

2 answers:

6 0

Answer: The force acting on the proton of charge 1.5 x10-19 C moving with velocity 1.5 x10-19 C under the influence of a magnetic field of 0.7 T will be 3.15×10^-13 N.

Explanation: To find the answer we need to know more about the Lorentz magnetic force.

<h3>What is the Lorentz magnetic force acting on the proton?</h3>

Consider a proton of charge q moving with a velocity v in a magnetic field, then the Lorentz magnetic force exerted on the proton can be expressed as,

F= q (v× B)

$F= qvBsin\alpha$ where, $\alpha$ is the angle between v and B.

In the question, it is given that,

$B=0.7 T\\q=1.5*10^{-19}C\\v= 3*10^{6}m/s.\\\alpha =90 degree.\\$ because, from the question it is clear that the proton is moving along x axis and the magnetic field is along the y axis.

Thus, we can find the force acting on the proton as,

$F=qvBsin\alpha =1.5*10^{-19}C*3*10^6 m/s*0.7T*sin (90)\\F=3.15*10^{-13}N$

Thus, we can conclude that the Lorentz force acting on the proton will be 3.15×10^-13 N.

Learn more about the Lorentz magnetic force here:

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ivann1987 [24]2 years ago

3 0

In response to a magnetic field of 0.7 T, a proton with a charge of 1.5 x 10-19 C travelling at a speed of 1.5 x 10-19 C will experience a force of 3.15 x 10^-13 N.

We need to learn more about the Lorentz magnetic force in order to locate the solution.

<h3>What does the proton experience as the Lorentz magnetic force?</h3>

If you imagine a proton with charge q travelling at speed v in a magnetic field, you can write down the Lorentz magnetic force acting on the proton as,

F= Q (v× B)

$F=QvBsin\alpha$

$\alpha$ the angle between v and B is, where.

It is stated in the query that, the magnetic field is along the y axis and the proton is travelling along the x axis. Thus, the angle will be 90 degrees.

As a result, we can identify the proton's driving force as,

$F=3.15*10^{-13}N$

Thus, we can infer that the proton will be subject to a 3.15 10^-13 N Lorentz force.

Learn more about the magnetic force of Lorentz here:

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Answer:

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2 years ago

A 10.0 N package of whole wheat flour is suddenly placed on the pan of a scale such as you find in grocery stores. The pan is su

inna [77]

Answer:

0.025 m

Explanation:

From the question,

Applying Hook's law

F = ke................... Equation 1

Where F = Force, k = spring constant of the scale, e = maximum distance at which the spring will compress.

make e the subject of the equation

e = F/k....................... Equation 2

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3 years ago

How fast does a 2 MeV fission neutron travel through a reactor core?

Artemon [7]

Answer:

The answer is $1.956 \times 10^7\ m/s$

Explanation:

The amount of energy is not enough to apply the relativistic formula of energy $E = mc^2$ , so the definition of energy in this case is

$E = \frac{1}{2}m v^2$ .

From the last equation,

$v= \sqrt{2E/m}$

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and the mass of the neutron is

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3 years ago

A (20*20) cm² loop has a resistance of 0.10 Ω. A magnetic field perpendicular to the loop is B = 4t - 2t², where B is in tesla a

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Answer with Explanation:

We are given that

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B= $4t-2t^2$

We know that magnetic flux

$\phi=BA$

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