Question

A proton moving along the positive x-axis enters a uniform magnetic field which is directed along the

Answer 1

Answer: The force acting on the proton of charge ​1.5 x10-19 C moving with velocity 1.5 x10-19 C under the influence of a magnetic field of 0.7 T will be 3.15×10^-13 N.

Explanation: To find the answer we need to know more about the Lorentz magnetic force.

What is the Lorentz magnetic force acting on the proton?

• Consider a proton of charge q moving with a velocity v in a magnetic field, then the Lorentz magnetic force exerted on the proton can be expressed as,

                                  F= q (v× B)

                               $F= qvBsin\alpha$  where, $\alpha$ is the angle between v and B.

• In the question, it is given that,

                                $B=0.7 T\\q=1.5*10^{-19}C\\v= 3*10^{6}m/s.\\\alpha =90 degree.$ because, from the question it is clear that the proton is moving along x axis and the magnetic field is along the y axis.

• Thus, we can find the force acting on the proton as,

                      $F=qvBsin\alpha =1.5*10^{-19}C*3*10^6 m/s*0.7T*sin (90)\\F=3.15*10^{-13}N$

Thus, we can conclude that the Lorentz force acting on the proton will be 3.15×10^-13 N.

Learn more about the Lorentz magnetic force here:

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Answer 2

In response to a magnetic field of 0.7 T, a proton with a charge of 1.5 x 10-19 C travelling at a speed of 1.5 x 10-19 C will experience a force of 3.15 x 10^-13 N.

We need to learn more about the Lorentz magnetic force in order to locate the solution.

What does the proton experience as the Lorentz magnetic force?

• If you imagine a proton with charge q travelling at speed v in a magnetic field, you can write down the Lorentz magnetic force acting on the proton as,

                                      F= Q (v× B)

                                   $F=QvBsin\alpha$

$\alpha$ the angle between v and B is, where.

• It is stated in the query that, the magnetic field is along the y axis and the proton is travelling along the x axis. Thus, the angle will be 90 degrees.

• As a result, we can identify the proton's driving force as,

                           $F=3.15*10^{-13}N$

Thus, we can infer that the proton will be subject to a 3.15 10^-13 N Lorentz force.

Learn more about the magnetic force of Lorentz here:

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