Answer:
1. C
2. D
Explanation:
<em>1</em><em>.</em><em> </em><em>as </em><em>the </em><em>object </em><em>is </em><em>stationary </em><em>despite </em><em>Jamal </em><em>applying </em><em>100N</em><em> </em><em>forces</em><em>, </em><em>it </em><em>suggests </em><em>that </em><em>the </em><em>object </em><em>i</em><em>s </em><em>applying </em><em>an </em><em>equal </em><em>amount </em><em>of </em><em>force </em><em>on</em><em> </em><em>the </em><em>opposite</em><em> </em><em>direction </em><em>that </em><em>is </em><em>opposing </em><em>the </em><em>force </em><em>applied</em><em> </em><em>by </em><em>Jamal.</em>
<em>2</em><em>.</em><em> </em><em>inertia </em><em>is</em><em> </em><em>a property of matter by which it continues in its existing state of rest or uniform motion in a straight line, unless that state is changed by an external force.</em><em> </em>
<em>hope </em><em>it</em><em> helps</em><em>. </em><em>:</em><em>)</em>
Answer:
a
Explanation:
because it has more energy
Answer:
F = - 3.53 10⁵ N
Explanation:
This problem must be solved using the relationship between momentum and the amount of movement.
I = F t = Δp
To find the time we use that the average speed in the contact is constant (v = 600m / s), let's use the uniform movement ratio
v = d / t
t = d / v
Reduce SI system
m = 26 g ( 1 kg/1000g) = 26 10⁻³ kg
d = 50 mm ( 1m/ 1000 mm) = 50 10⁻³ m
Let's calculate
t = 50 10⁻³ / 600
t = 8.33 10⁻⁵ s
With this value we use the momentum and momentum relationship
F t = m v - m v₀
As the bullet bounces the speed sign after the crash is negative
F = m (v-vo) / t
F = 26 10⁻³ (-500 - 630) / 8.33 10⁻⁵
F = - 3.53 10⁵ N
The negative sign indicates that the force is exerted against the bullet
Answer:
Gravitational field strength =weight/mass
Explanation:
14.8N/4.0kg
3.7N/kg
