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3 years ago

An example of a household appliance with a low and high power rating

Physics

1 answer:

olchik [2.2K]3 years ago

5 0

Answer:

Explanation:

There are countless household appliances in every single house. One appliance with a low power rating would be a ceiling fan. On average ceiling fans consume roughly 60w and are found in the majority of houses. On the other side of the spectrum, we have a high power-rating appliance such as a microwave. Microwaves use anywhere between 1000w to 1800w of power in order to function correctly. This is very large power consumption and one of the highest power ratings found for appliances in a household.

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Suppose that the separation between two speakers A and B is 4.80 m and the speakers are vibrating in-phase. They are playing ide

Hatshy [7]

Answer:

$X=8.44m$

Explanation:

From the question we are told that

Distance b/w A&B $x=4.80m$

Frequency $f=134Hz$

Sound speed $v=343m/s$

Generally the equation for wavelength is mathematically given as

$\lambda=v/f$

$\lambda/2=1/2*v/f$

$\lambda/2=1/2*\frac{343}{135}$

$\lambda/2=1.27037037$

Generally the destructive interference X is mathematically given by

$\sqrt{4.8^2 +X^2} -X=1.27037037\\$

$23.04+BC^2=X^2+1.613+2.54*X$

Therefore the destructive interference is

$X=8.44m$

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3 years ago

What is the definition of work in Physics?

Degger [83]

Answer:

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4 years ago

Identify two factors that determine the intensity of sound

anastassius [24]

Amplitude and distance.

5 0

3 years ago

Example 4:

earnstyle [38]

Answer:

Given speed of light in diamond =1.24*10m/s

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3 0

3 years ago

An ultrasound unit is being used to measure a patient's heartbeat by combining the emitted 2.0 MHz signal with the sound waves r

alexandr402 [8]

Hi there,
for this question we have:
Signal 2.0 MHz = Emitted so we can call it $f_e$
and we need the Reflected = $f_{r}$
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted).
we also know: ΔBeat frequency(max) = 560 Hz = $f_{b}$
so we have:
$f_{e}$ - $f_{r}$ = $f_{b}$
so frequency of Reflected is:
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz = $f_{r}$
now you know that Lambda = v/f
so if we find the lambda with our Emitted then we can find v with the Reflected:
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m
=> $v_{max}$ = (lambda)( $f_{r}$
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s
so the $v_{max}$ is equal to 1532 m/s :)))
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day

8 0

3 years ago

An example of a household appliance with a low and high power rating​

An example of a household appliance with a low and high power rating