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ale4655 [162]
2 years ago
13

Compute your average velocity in the following two cases: (a) You walk 85.5 m at a speed of 1.41 m/s and then run 85.5 m at a sp

eed of 4.15 m/s along a straight track. (b) You walk for 1.00 min at a speed of 1.41 m/s and then run for 1.32 min at 4.15 m/s along a straight track.
Physics
1 answer:
Vikki [24]2 years ago
4 0

Answer:

a) The average speed was V = 2.1 m/s

b) The average speed was V = 2.97 m/s

Explanation:

The average velocity is given by the distance travelled by the time it took to travel it.

a) In this case we have two stages, both with the same length of 85.5 m so the total distance will be the sum of both that is 85.5 + 85.5 = 171 m. We are then given the speed for both stages. In order to calculate the average speed we need to compute the total time it took to complete the route, to do that we need to calculate the time it took to complete each stage. So we have:

t_1 = S1/V1 = 85.5/1.41 =  60.64 s

t_2 = S2/V2 = 85.5/4.15 = 20.60s

total time = t1 + t2 = 60.64 + 20.60 = 81.24 s

V = total length/ total time = 171/81.24 = 2.1 m/s

b) In this case we have the time it took for each stage, they're given in minutes so the first thing we need to do is convert them to seconds, we do that by multiplying it by 60. We have:

t1 = 1*60 = 60 s

t2 = 1.32*60 = 79.2 s

total time = 139.2 s

We can now compute the length of each stage, we do that by multiplying the time it took to complete each stage by the speed of each. We have:

S1 = 60*1.41 = 84.6 m

S2 = 79.2*4.15 = 328.68 m

total length = 84.6 + 328.6 = 413.28 m

V = total length / total time = 413.28 / 139.2 = 2.97 m/s

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Answer:

A

Explanation:

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2 years ago
A 15.0 Ohms resistor is connected in series to a 120V generator and two 10.0 Ohms resistors that are connected in parallel to ea
Nostrana [21]

Hi there! :)

Reference the diagram below for clarification.

1.

We must begin by knowing the following rules for resistors in series and parallel.

In series:
R_T = R_1 + R_2 + ... + R_n

In parallel:
\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}

We can begin solving for the equivalent resistance of the two resistors in parallel using the parallel rules.

\frac{1}{R_{T, parallel}} = \frac{1}{10} + \frac{1}{10}\\\\\frac{1}{R_{T, parallel}} = \frac{2}{10} = \frac{1}{5}\\\\R_{T, parallel} = 5\Omega

Now that we have reduced the parallel resistors to a 'single' resistor, we can add their equivalent resistance with the other resistor in parallel (15 Ohm) using series rules:
R_T = 15 + 5\\\\\boxed{R_T = 20 \Omega}

2.

We can use Ohm's law to solve for the current in the circuit.

i = \frac{V}{R_T}\\\\i = \frac{120}{20} = \boxed{6 A}

3.

For resistors in series, both resistors receive the SAME current.

Therefore, the 15Ω resistor receives 6A, and the parallel COMBO (not each individual resistor, but the 5Ω equivalent when combined) receives 6A.

In this instance, since both of the resistors in parallel are equal, the current is SPLIT EQUALLY between the two. (Current in parallel ADDS UP). Therefore, an even split between 2 resistors of 6 A is <u>3A for each 10Ω resistor</u>.

4.

Since the 15.0 Ω resistor receives 6A, we can use Ohm's Law to solve for voltage.

V = iR\\\\V = (6)(15) = \boxed{90 V}

4 0
1 year ago
The low-frequency speaker of a stereo set has a surface area of 0.06 m2 and produces 2.03 W of acoustical power. What is the int
zimovet [89]

Answer:

33.83W/m²

Explanation:

The intensity of the speake at the surface is

I = P/A

I = 2.03W / 0.06m²

I = 33.83W/m²

8 0
2 years ago
What types of electromagnetic radiation does the sun emit?
Ksju [112]

Answer:

https://gml.noaa.gov/education/info_activities/pdfs/LA_radiation.pdf

Explanation:

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2 years ago
If each of the three rotor helicopter blades is 3.50 m long and has a mass of 120 kg , calculate the moment of inertia of the th
devlian [24]

Answer:

1470kgm²

Explanation:

The formula for expressing the moment of inertial is expressed as;

I = 1/3mr²

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r is the radius

Since there are three rotor blades, the moment of inertia will be;

I = 3(1/3mr²)

I = mr²

Given

m = 120kg

r = 3.50m

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Moment of inertia

Substitute the given values and get I

I = 120(3.50)²

I = 120(12.25)

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Hence the moment of inertial of the three rotor blades about the axis of rotation is 1470kgm²

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3 years ago
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