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miskamm [114]
3 years ago
5

An ice cube is placed on a hot stove. Which of these statements best describes how heat moves between the ice cube and the stove

? (1 point)
A.Heat moves from the ice cube to the stove through conduction.
B. Heat moves from the stove to the ice cube through conduction.
C.Heat moves from the ice cube to the stove through convection.
D.Heat moves from the stove to the ice cube through convection.
Physics
2 answers:
Tanzania [10]3 years ago
6 0
B! Conduction is touch, so the heat traveled through touch from th stove to the ice cube, therefore melting it
Sergio [31]3 years ago
5 0

Answer: B. Heat moves from the stove to the ice cube through conduction.

Explanation:

There are three modes of heat transfer- conduction, convection and radiation.

When two objects which are not in thermal equilibrium come in contact, heat transfer takes place via conduction. The heat transfers from hotter object to the cooler one.

In convection, there is bulk movement of fluid which transfers heat from heat source to the the cooler region of the fluid.

Heat radiation can travel through vacuum from the source of heat.

In the given situation, ice cube is placed on a heat stove. There is a direct contact between the two objects. Heat would transfer from hot stove to cube till the two are in thermal equilibrium.

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Answer:

The mass of the liquid = 10538 kg

Explanation:

The pressure in a liquid is

P = ρgh ......................... Equation 1

ρ = P/gh ...................... Equation 2

Where P = pressure, ρ = density, g = acceleration due to gravity, h = height.

Given: p = 1.3 atm, h = 2.0 m, g = 9.81 m/s²

If,  1 atm = 1.013×10⁵ N/m²

Then, P = 1.3×1.013×10⁵ N/m² = 1.3169×10⁵ N/m²

Substituting in equation 2,

ρ  =  1.3169×10⁵/(9.81×2)

ρ =   1.3169×10⁵/19.62

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But Density,

ρ  = m/v  

m =  ρ × v........................ Equation 3

Where m = mass of the liquid, v = volume of the liquid in the vat

v = πd²h/4, where d = diameter = 1.0 m, h = 2.0 m.

v = 3.14(1)²×2/4

v = 1.57 m³ also,  ρ =  6712.03 kg/m³.

Substituting into equation 3

m = 1.57×6712.03

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Thus the mass of the liquid = 10538 kg

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