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miskamm [114]
3 years ago
5

An ice cube is placed on a hot stove. Which of these statements best describes how heat moves between the ice cube and the stove

? (1 point)
A.Heat moves from the ice cube to the stove through conduction.
B. Heat moves from the stove to the ice cube through conduction.
C.Heat moves from the ice cube to the stove through convection.
D.Heat moves from the stove to the ice cube through convection.
Physics
2 answers:
Tanzania [10]3 years ago
6 0
B! Conduction is touch, so the heat traveled through touch from th stove to the ice cube, therefore melting it
Sergio [31]3 years ago
5 0

Answer: B. Heat moves from the stove to the ice cube through conduction.

Explanation:

There are three modes of heat transfer- conduction, convection and radiation.

When two objects which are not in thermal equilibrium come in contact, heat transfer takes place via conduction. The heat transfers from hotter object to the cooler one.

In convection, there is bulk movement of fluid which transfers heat from heat source to the the cooler region of the fluid.

Heat radiation can travel through vacuum from the source of heat.

In the given situation, ice cube is placed on a heat stove. There is a direct contact between the two objects. Heat would transfer from hot stove to cube till the two are in thermal equilibrium.

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A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and ret
emmasim [6.3K]

f' = frequency observed by the police car after sound reflected from the vehicle and comes back to police car = 1250 Hz

f = frequency emitted by the police car  = 1200 Hz

V = speed of sound = 340 m/s

v = speed of vehicle = ?

frequency observed by the police car is given as

f' = f (V + v)/(V - v)

inserting the values in the above equation

1250 = 1200 (340 + v)/(340 - v)

v = 6.9 m/s

4 0
3 years ago
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g A cylinder of mass m is free to slide in a vertical tube. The kinetic friction force between the cylinder and the walls of the
sdas [7]

Answer:

The vertical distance is  d = \frac{2}{k} *[mg + f]

Explanation:

From the question we are told that

   The mass of the cylinder is  m

    The kinetic frictional force is  f

Generally from the work energy theorem

    E  =  P +  W_f

Here E the the energy of the spring which is increasing and this is mathematically represented as

       E =  \frac{1}{2} * k  *  d^2

Here k is the spring constant

        P is the potential energy of the cylinder which is mathematically represented as

     P  = mgd

And

     W_f  is the workdone by friction which is mathematically represented as

      W_f  =  f *  d

So

    \frac{1}{2} * k  *  d^2 =  mgd +  f *  d

=>    \frac{1}{2} * k  *  d^2 =  d[mg +  f    ]

=>  \frac{1}{2} * k  *  d =  [mg +  f    ]

=> d = \frac{2}{k} *[mg + f]

5 0
4 years ago
A high-jump athlete leaves the ground, lifting her center of mass 1.8 m and crossing the bar with a horizontal velocity of 1.4 m
Romashka [77]

Answer:

The minimum speed when she leave the ground is 6.10 m/s.

Explanation:

Given that,

Horizontal velocity = 1.4 m/s

Height = 1.8 m

We need to calculate the minimum speed must she leave the ground

Using conservation of energy

K.E+P.E=P.E+K.E

\dfrac{1}{2}mv_{1}^2+0=mgh+\dfrac{1}{2}mv_{2}^2

\dfrac{v_{1}^2}{2}=gh+\dfrac{v_{2}^2}{2}

Put the value into the formula

\dfrac{v_{1}^2}{2}=9.8\times1.8+\dfrac{(1.4)^2}{2}

\dfrac{v_{1}^2}{2}=18.62

v_{1}=\sqrt{2\times18.62}

v_{1}=6.10\ m/s

Hence, The minimum speed when she leave the ground is 6.10 m/s.

6 0
3 years ago
The change in momentum experienced by a object is equivalent to the...
Papessa [141]

Answer: C (impulse acting on the object)

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From Newtons II law

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                = m. v/t               <em>since a = rate of change of velocity.</em>

<em>              </em>F . t = m . v

F . t is known as impulse momentum

8 0
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AnnyKZ [126]

Answer:B

Explanation: I think this is the answer

8 0
3 years ago
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