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miskamm [114]
3 years ago
5

An ice cube is placed on a hot stove. Which of these statements best describes how heat moves between the ice cube and the stove

? (1 point)
A.Heat moves from the ice cube to the stove through conduction.
B. Heat moves from the stove to the ice cube through conduction.
C.Heat moves from the ice cube to the stove through convection.
D.Heat moves from the stove to the ice cube through convection.
Physics
2 answers:
Tanzania [10]3 years ago
6 0
B! Conduction is touch, so the heat traveled through touch from th stove to the ice cube, therefore melting it
Sergio [31]3 years ago
5 0

Answer: B. Heat moves from the stove to the ice cube through conduction.

Explanation:

There are three modes of heat transfer- conduction, convection and radiation.

When two objects which are not in thermal equilibrium come in contact, heat transfer takes place via conduction. The heat transfers from hotter object to the cooler one.

In convection, there is bulk movement of fluid which transfers heat from heat source to the the cooler region of the fluid.

Heat radiation can travel through vacuum from the source of heat.

In the given situation, ice cube is placed on a heat stove. There is a direct contact between the two objects. Heat would transfer from hot stove to cube till the two are in thermal equilibrium.

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An airplane traveling at one third the speed of sound (i.e., 114 m/s) emits a sound of frequency 3.72 kHz. At what frequency doe
nlexa [21]

Answer:

f'=5.58kHz

Explanation:

This is an example of the Doppler effect, the formula is:

f'=\frac{(v+v_o)}{(v+v_s)}f

Where f is the actual frequency, f' is the observed frequency, v is the velocity of the sound waves, v_o the velocity of the observer (which is negative if the observer is moving away from the source)  and v_s the velocity of the source  (which is negative if is moving towards the observer). For this problem:

f=3.72kHz\\v=342m/s\\v_o=0m/s\\v_s=-114m/s

f'=\frac{(342+0)}{(342-114)}3.72\times10^3\\f'=\frac{342}{228}3.72\times10^3\\f'=(1.5)3.72\times10^3\\f'=5580Hz=5.58kHz

5 0
3 years ago
according to newton's second law of motion of the net force acting on the object increases while the mass of the object remains
Licemer1 [7]

Answer:

The Acceleration will increase

Explanation:

Newton's Second Law of motion: It states that the rate of change of momentum is directly proportional to the applied force and takes places along the direction of the force.

It can be expressed mathematically as,

F ∝ m(v-u)/t

Where (v-u)/t = a

F  = kma.

F = force, m = mass of the body, a = acceleration, k = constant of proportionality which tend to unity for a unit force, a unit mass, and a unit acceleration.

Therefore,

F = ma.

From the equation above,

If the net force acting on a body increase, while the mass of the body remains constant, the acceleration will also increase.

4 0
3 years ago
A train accelerates to a velocity of 500 m/s over time of 2s. The acceleration it experienced was 50m/s2. What was its initial v
ValentinkaMS [17]

Explanation:

We know ,

  • v = u + at
  • u = v - at
  • u = 500 - 2*50
  • u = 400 m/s
7 0
3 years ago
A boy throws a ball with an initial velocity of 19.6 m/s. What maximum height does the ball reach?
Wewaii [24]
<h2>Hello!</h2>

The answer is: 19.59 m

<h2>Why?</h2>

Since there is no information about the launch type, we can assume that the ball is thrown vertically upward.

When the ball reaches the maximum height, just at that moment, the velocity turns to 0, and after that moment, the ball starts falling, so:

We will use the following formula:

Vf^2=Vi^2+2*g*s

Where:

Vf= Final velocity = 0

Vi= Initial velocity = \frac{19.6m}{s}

g = Gravity Acceleration = \frac{9.81m}{s^{2} }

s = Traveled distance

0=19.6^2+2*-9.81*s\\s=\frac{19.6^2}{2*9.81}=\frac{384.16}{19.62}=19.59m

Have a nice day!

8 0
3 years ago
Please Help Me!!!........​
vesna_86 [32]

Answer:

1.Siddartha Gautama

2.no single founder

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7 0
3 years ago
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