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Sholpan [36]
3 years ago
14

If you have 600 g of c6h12o6 then how many grams of oxygen are there

Chemistry
1 answer:
Shalnov [3]3 years ago
7 0
 <span>so your ratio for the equation is 1 glucose + 6 oxygen = 6 carbon dioxide + 6 water 

those ratios will all be in moles, and will all be based on the number of moles of your limiting reagent. We assume that you have unlimited oxygen, so glucose must be limiting. The molar mass for glucose is 180 grams (you can get more accurate if you need, this is just the number I am using). 

100 g / 180 g/mol = 0.556 moles of glucose. 
since we will need six times the moles of glucose in oxygen... 
6 x .556 = 3.33 moles of O2 
multiply by the molar mass of O2 for the mass of oxygen needed... 
3.33 x 32 = 106.67 grams of O2 
since you are forming six times the moles of glucose in CO2 and H2O, you are forming 3.33 moles of each of these compounds as well.</span>
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3 years ago
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Group 7A (17) elements can gain one electron to attain a noble gas electron configuration. In combination with metal atoms that
Iteru [2.4K]

Answer:

The two statements are all True for group 7 and 8 elements.

Explanation:

The Group 7 elements are known as the halogens. They are reactive non-metals and are always found in compounds with other elements. Chlorine, bromine and iodine are all halogens.

Chlorine, bromine and iodine are the three common Group 7 elements. Group 7 elements form salts when they react with metals. The term ‘halogen’ means 'salt former'.

In addition to the discription given to norble gases in the question which is true, norble gases;

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5 0
3 years ago
A very hot cube of copper metal (32.5 g) is submerged into 105.3 g of water at 15.4 0C and it reach a thermal equilibrium of 17.
zysi [14]

Answer:

The initial temperature of the metal is 84.149 °C.

Explanation:

The heat lost by the metal will be equivalent to the heat gain by the water.  

- (msΔT)metal = (msΔT)water

-32.5 grams × 0.365 J/g°C × ΔT = 105.3 grams × 4.18 J/g °C × (17.3 -15.4)°C

-ΔT = 836.29/12.51 °C

-ΔT = 66.89 °C

-(T final - T initial) = 66.89 °C

T initial = 66.89 °C + T final

T initial = 66.89 °C + 17.3 °C

T initial = 84.149 °C.

7 0
3 years ago
About the instruction that marko gave to hinano
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Mannoheptulose is a sugar found in avocados. If each C-C bond contains 76 kcal of energy and each C-H bond contains 91 kcal, how
nadya68 [22]

Answer:

Total Kcal energy produced in the catabolism of mannoheptulose = 1184 Kcal

Explanation:

The molecular formula of mannoheptulose is C₇H₁₄O₇.

The structure is as shown in the attachment below.

Number of C-C bonds present in mannoheptulose = 6

Number of C-H bonds present in mannoheptulose = 8

Since the each C-C bond contains 76 Kcal of energy,

Amount of energy present in six C-C bonds = 6 * 76 = 456 Kcal

Also, since each C-H bond contains 91 Kcal of energy;

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Total Kcal energy produced in the catabolism of mannoheptulose = 456 + 728 = 1184 Kcal

6 0
3 years ago
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