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Otrada [13]
3 years ago
8

How to calculate the mass of solid sodium hydroxide needed to prepare 200 ml of a 0.040m solution. if one pellet of sodium hydro

xide weighs 0.170g, how many pellets should be dissolved?
Chemistry
1 answer:
lbvjy [14]3 years ago
4 0
<span>0.496 g of NaOH required 3 pellets. First, determine the molar mass of NaOH. Atomic weight sodium = 22.989769 Atomic weight hydrogen = 22.989769 Atomic weight oxygen = 15.999 Molar mass NaOH = 22.989769 + 22.989769 + 15.999 = 61.978538 g/mol Now determine how many moles of NaOH we need. Multiply desired volume by desired molarity. So 0.200 l * 0.040 mol/l= 0.008 mol To get the mass, then multiply by the molar mass, so 0.008 mol * 61.978538 g/mol = 0.495828304 g Since we have the NaOH in pellet form, divide the desired mass by the mass of each pellet. So 0.495828304 g / 0.170 g/pellet = 2.916637082 pellets You'll need 3 pellets. To get closer to the desired molarity, I would recommend increasing the amount of solution being prepared if you can accurately measure the larger volume.</span>
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Answer:

HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)

Explanation:

Hello there!

In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:

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Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:

HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)

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