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Savatey [412]
2 years ago
13

Which of the following manufacturing tools machines parts by moving the part into the cutting tool (instead of moving the cuttin

g tool into the part).
A.) Lathe
B.) Drill Press
C.) Injection Molder
D.) Milling Machine
Engineering
1 answer:
Verdich [7]2 years ago
5 0

Lathe is the manufacturing tools machines parts by moving the part into the cutting tool.

<u>Explanation:</u>

  • The metals, other materials or wood are shaped as pieces using the machine tool which is lathe.
  • Lathe is identified as three kinds: Engine lathe, Special purpose lathe, Turret lathe.
  • Semi-portable and bench mounted are smaller ones.
  • Floor mounted are large lathe it needs special transportations to move.
  • Engine lathe can be moved from one area to another because its not too large. The lathe which is adapted many operations are used in maitanance shop.
  • Special purpose lathe and Turret lathe is used in mass production.
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3 years ago
The theoretical maximum specific gravity of a mix at 5.0% binder content is 2.495. Using a binder specific gravity of 1.0, find
PSYCHO15rus [73]

Answer:

The theoretical maximum specific gravity at 6.5% binder content is 2.44.

Explanation:

Given the specific gravity at 5.0 %  binder content 2.495

Therefore

95 % mix + 5 % binder  gives S.G. = 2.495

Where the  binder is S.G. = 1, Therefore

Per 100 mass unit we have (Mx + 5)/(Vx + 5) = 2.495

(95 +5)/(Vx +5) = 2.495

2.495 × (Vx + 5) = 100

Vx =35.08 to 95

Or density of mix = Mx/Vx = 95/35.08 = 2.7081

Therefore when we have 6.5 % binder content, we get

Per 100 mass unit

93.5 Mass unit of Mx has a volume of

Mass/Density = 93.5/2.7081 = 34.526 volume units

Therefore we have

At 6.5 % binder content.

(100 mass unit)/(34.526 + 6.5) = 2.44

The theoretical maximum specific gravity at 6.5% binder content = 2.44.

3 0
3 years ago
Which of the following should you avoid when pulling over to the curb?
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Answer:

Explanation:

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7 0
3 years ago
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4 0
3 years ago
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The fracture toughness of a stainless steel is 137 MPa*m12. What is the tensile impact load sustainable before fracture that a r
Charra [1.4K]

Answer:

7.7 kN

Explanation:

The capacity of a material having a crack to withstand fracture is referred to as fracture toughness.

It can be expressed by using the formula:

K = \sigma Y \sqrt{\pi a}

where;

fracture toughness K = 137 MPam^{1/2}

geometry factor Y = 1

applied stress \sigma = ???

crack length a = 2mm = 0.002

∴

137 =\sigma \times 1  \sqrt{ \pi \times 0.002 }

137 =\sigma \times 0.07926

\dfrac{137}{0.07926} =\sigma

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