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saveliy_v [14]
3 years ago
11

Three possible career opportunities in embedded systems engineering

Engineering
1 answer:
timama [110]3 years ago
3 0

Answer:Embedded Software Engineer (firmware)

- System Software Engineer (kernal & RTOS)

- Application Software Engineer (device drivers)

- Software Test Engineer.

- Embedded Hardware Engineer.

- Embedded System Trainer.

- Marketing & Sales Executive.

Explanation:

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When do you know if you start volly ball
igomit [66]
Answer You ask your coach
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4 years ago
Using the tables for water determine the specified property data at the indicated state. For H2O at T = 140 °C and v = 0.2 m3/kg
Dennis_Churaev [7]

Answer:

h = 1429.74\,\frac{kJ}{kg}

Explanation:

The determination of any further properties requires the knowledge of two independent properties. (Temperature and specific volume in this case). The specific volumes for saturated liquid and vapor at 140 °C are, respectively:

\nu_{f} = 0.001080\,\frac{m^{3}}{kg}

\nu_{g} = 0.50850\,\frac{m^{3}}{kg}

Since \nu_{f} < \nu < \nu_{g}, it is a liquid-vapor mixture. The quality of the mixture is:

x = \frac{\nu-\nu_{f}}{\nu_{g}-\nu_{f}}

x = \frac{0.2\,\frac{m^{3}}{kg} - 0.001080\,\frac{m^{3}}{kg} }{0.50850\,\frac{m^{3}}{kg} - 0.001080\,\frac{m^{3}}{kg} }

x = 0.392

The specific enthalpies for saturated liquid and vapor at 140 °C are, respectively:

h_{f} = 589.16\,\frac{kJ}{kg}

h_{g} = 2733.5\,\frac{kJ}{kg}

The specific enthalpy is:

h = h_{f}+x\cdot (h_{g}-h_{f})

h = 589.16\,\frac{kJ}{kg}+0.392\cdot \left( 2733.5\,\frac{kJ}{kg} - 589.16\,\frac{kJ}{kg} \right)

h = 1429.74\,\frac{kJ}{kg}

6 0
4 years ago
Read 2 more answers
When you apply for your driver license, you consent to take a ____ test when asked to do so by a law enforcement officer. memory
n200080 [17]

Answer:

Driving test

Explanation:

Usually according to laws in countries worldwide, to be licenced to drive, one is required to go through a driving school to learn the ethics and rules of driving.

4 0
2 years ago
What are the main causes of injuries when using forklifts?
Julli [10]

Answer:

1, 3, 4, 5

Explanation:

just did it

4 0
3 years ago
Three masses are attached to a uniform meter stick, as shown in Figure 12.9. The mass of the meter
sp2606 [1]

At equilibrium, the sum of clockwise and anticlockwise moments about a point is zero

The mass of that balances the system is \underline {316.\overline 6} kg

The normal reaction force at the fulcrum is <u>5,804.25 N</u>

Rason:

The mass of the stick = 150.0 g

Mass m₁ on the left = 50.0 g, location = 30 cm to the left of m₂

Mass m₂ on the left = 75.0 g, location = 40 cm to the left of the fulcrum

Mass m₃ on the right of the fulcrum. location = 30 cm to the right of the fulcrum

Required:

To find the mass of m₃

Solution:

Taking moment about the fulcrum, we have;

50 × (30 + 40) + 75 × (40) + 150 × 20 = m₃ × 30

9,500 = m₃×30

m_3 = \dfrac{9,500}{30} = 316. \overline 6

The mass of that balances the system when it is attached at the right end of the stick, m₃ = 316.\overline 6 kg

Normal reaction at the fulcrum = (50 + 75 + 150 +  316.\overline 6) × 9.81 = 5804.25

The normal reaction at the fulcrum is 5,804.25 N

Learn more about the moment of a force here:

brainly.com/question/19464450

8 0
2 years ago
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