Answer:
116.3 electrons
Explanation:
Data provided in the question:
Time, t = 2.55 ps = 2.55 × 10⁻¹² s
Current, i = 7.3 μA = 7.3 × 10⁻⁶ A
Now,
we know,
Charge, Q = it
thus,
Q = (7.3 × 10⁻⁶) × (2.55 × 10⁻¹²)
or
Q = 18.615 × 10⁻¹⁸ C
Also,
We know
Charge of 1 electron, q = 1.6 × 10⁻¹⁹ C
Therefore,
Number of electrons past a fixed point = Q ÷ q
= [ 18.615 × 10⁻¹⁸ ] ÷ [ 1.6 × 10⁻¹⁹ ]
= 116.3 electrons
Answer:
<h2>True Most Especially in the field of Automotive Engineering</h2>
Explanation:
Normally, before the introduction of vehicle diagnostics when a vehicle, mostly automobile/car break down, one could be the vehicle mechanic would only suspect one or two related faults based on the present working condition of the car, the mechanic would perform some trial and error before he could fix the car.
But in recent times, the introduction of vehicle diagnostics devices and software has changed the order as vehicles can be connected to a computer that will scan and tell what the problem is before a possible fix.
Answer:
#include<iostream>
using namespace std;
int main()
{
double data[3][5],avg,least,most,total;
int leastNum,mostNum;
for(int i=0;i<3;i++)
{
cout<<"Enter quantity of food for monkey "<<i+1<<":\n";
for(int j=0;j<5;j++)
{
cout<<"Day "<<j+1<<": ";
cin>>data[i][j];
}
}
least = data[0][0];
most = data[0][0];
for(int i = 0;i<3;i++)
{
for(int j = 0;j<5;j++)
{
total+=data[i][j];
if(data[i][j]>most)
{
most=data[i][j];
mostNum=i+1;
}
if(data[i][j]<least)
{
least=data[i][j];
leastNum=i+1;
}
}
}
avg=total/5.0;
cout<<"Average food eaten in a day by all the 3 monkeys: "<<avg<<endl;
cout<<"Most amount of food eaten in a day: "<<most<<" by monkey: "<<mostNum<<endl;
cout<<"Least amount of food eaten in a day: "<<least<<" by monkey: "<<leastNum<<endl;
return 0;
}
Okey du we went on a date lastnight and all okay
Fast sheet
