Question

A volleyball dug out by the opponent popped straight up into the air. It takes 2.05 seconds for the ball to reach its peak. Determine the height to which the ball flies. So far, I got the givens of t=2.05 seconds x=? a=9.8 meter per seconds squared final velocity=0 m/s they might be wrong though so help please!!!!

Answer 1

Answer:

The height to which the ball flies is 86.6 m.

Explanation:

Given that,

Time = 2.05 sec

Acceleration = 9.8 m/s²

We need to calculate the initial velocity of volleyball

Using equation of motion

$v=u-at$

Where, u = initial velocity

a = acceleration

t = time

Put the value into the formula

$0=u-9.8\times(2.05)^2$

$u=41.2\ m/s$

We need to calculate the height of the the ball

Using equation of motion

$v^2=u^2-2ah$

Put the value into the formula

$0=(41.2)^2-2\times9.8\times h$

$h=\dfrac{(41.2)^2}{2\times9.8}$

$h=86.6\ m$

Hence, The height to which the ball flies is 86.6 m.