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Bumek [7]
3 years ago
6

Dysentery can lead to ________ and/or organ failure if medical attention is not sought in time.

Biology
1 answer:
klasskru [66]3 years ago
4 0

Answer:

Option-B

Explanation:

Dysentery is an abnormal condition that is caused by the infection of the intestine in humans. The infection could be caused by the bacteria or the amoeba.

The disease can be characterized by the cramps in the stomach, diarrhea, and the loss of blood through feces.

Untreated dysentery can lead to the loss of a large amount of blood through feces and will lower the amount of blood in humans.

This severe loss of blood will give rise to another disease called hypovolemic shock is which the heart fails to pump enough blood to the organs due to which the other organs of the body can fail to work properly.  This condition can lead to death.

Thus, Option-B is correct.

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Which of the following describes chaparral shrubs?. a.. short. b.. evergreen. c.. contain flammable oils. d.. all of the above
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3 0
3 years ago
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In a population of cats, the phenotypic frequency of black cats is 91%, and the phenotypic frequency of white cats is 9%. Assumi
Talja [164]

Answer:

1. Allele frequency of b = 0.09 (or 9%)

2. Allele frequency of B = 0.91 (0.91%)

3. Genotype frequency of BB = 0.8281 (or 82.81%)

4. Genotype frequency of Bb = 0.1638 (or 16.38%)

Explanation:

Given that:

p = the frequency of the dominant allele (represented here by B)  = 0.91

q = the frequency of the recessive allele (represented here by b)  = 0.09

For a population in genetic equilibrium:

p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)

(p + q)^2 = 1

Therefore:

p^2 + 2pq + q^2 = 1

in which:  

p^2 = frequency of BB (homozygous dominant)

2pq = frequency of Bb (heterozygous)

q^2 = frequency of bb (homozygous recessive)

p^2 = 0.91^2 = 0.8281

2pq = 2(0.91)(0.9) = 0.1638

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The herbivore population would starve and decrease as well.
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