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Musya8 [376]
3 years ago
13

I need answers for all of these please and thank you.

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0

I can't do the domain and range but here are the function answers:

1)N

2)N

3)Y

4)N

5)Y

6)Y

7)N

8)N

9)Y

I hope that helped. Sorry I couldn't do the other parts.

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HELP!!!!!!!!! ASP
Anarel [89]

Answer:

D

Step-by-step explanation:

What you need to do is find the slope of both lines. Perpendicular lines are the negative inverse of each other. The slope of the lie between points R and F is  (2-4)/(1+9)=-1/5. Now you need to find the line where the slop is 5. If you look at D, the slope of the line those points lie on is (25-15)/(4-2)=5 which makes D the answer.

3 0
3 years ago
Read 2 more answers
If x represents one of the equal sides of the triangle, then which equation can be used to solve the problem?
Maksim231197 [3]
X + 2(x + 4) = 32
3x + 8 = 32
3x = 24
x = 8

The lengths of the sides are  8, 12 and 12 (answer),
8 0
3 years ago
Challenge You have 2 different savings accounts. For Account​ A, the simple interest earned after months is ​$. For Account​ B,
Debora [2.8K]

Answer and Step-by-step explanation:

The computation is shown below;

As we know that

The simple interest is

Simple interest = Principal × rate × time

For Account A, the principal would be

2 = Principal × 3.2% × 3

So, the principal is $20.83

For account B, the principal would be

38.50 = Principal × 2.2% × 30

So, the principal is $58.33

Now the interest for both the accounts are as follows

For account 1

= $20.83 × 3.2%

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= $58.33 × 2.2%

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As it can be seen that the account 2 has the highest interest

The same is to be considered

7 0
2 years ago
8 fluid ounces time 1 quart​
myrzilka [38]

Answer:

0.25

Step-by-step explanation:

If one quart equals 32 ounces, then we multiply the volume by 32  

4 0
3 years ago
A circle with radius of 9 cm sits inside a circle with radius of 11
saul85 [17]
Ok so to answer this, we first need to figure out the area of both circles
we will use the formula A=πr²

so our two areas end up being 121π and 81π

now all we do is subtract the smaller from the larger

121π - 81π = 40π

shaded region = 40π
8 0
3 years ago
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