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Troyanec [42]
3 years ago
13

When we react a weak acid with a strong base of equal amounts and concentration, the component of the reaction that will have th

e greatest effect on the pH of the solution is:______.
a. the acid.
b. the base.
c. the conjugate acid.
d. the conjugate base.
Chemistry
1 answer:
vagabundo [1.1K]3 years ago
6 0

Answer:

d. the conjugate base.

Explanation:

The general reaction of a weak acid, HA, with a strong base YOH, is:

HA + YOH → A⁻ + H₂O + Y⁻

<em>Where A⁻ is the conjugate base of the weak acid and Y⁻ usually is a strong electrolyte.</em>

<em />

That means after he complete reaction you don't have weak acid nor strong base, just conjugate base that will be in equilibrium with water, thus (Strong electrolyte doesn't change pH:

A⁻ + H₂O ⇄ HA + OH⁻

As the equilibrium is producing OH⁻, the pH of the solution is being affected for the conjugate base

Right option:

<h3>d. the conjugate base. </h3>

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Is milk a solution, suspension, compound , colloid ?
kakasveta [241]

Answer:

Colloids (heterogeneous)

The difference between a colloid and a suspension is that the particles will not settle to the bottom over a period of time, they will stay suspended or float. An example of a colloid is milk. Milk is a mixture of liquid butterfat globules dispersed and suspended in water.

3 0
2 years ago
Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4
inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

4 0
2 years ago
You would know you were in the troposphere If?
lora16 [44]
It were raining on you
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3 years ago
If 14 moles of oxygen react with 14 moles of hydrogen to produce water, what is the
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7 0
2 years ago
What is 95°F on the Celsius scale?
GarryVolchara [31]
ºC = ( ºF - 32 ) / 1.8

ºC = 95 - 32 / 1.8

ºC = 63 / 1.8

= 35 ºC

hope this helps!

5 0
3 years ago
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