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Art [367]
3 years ago
9

Which of the statements listed below is negative aspect of a volcanic eruption?

Chemistry
1 answer:
mixas84 [53]3 years ago
5 0

Answer:

<em>C</em><em> </em><em>.</em><em> </em><em>the</em><em> </em><em>dramatic</em><em> </em><em>scenery</em><em> </em><em>created</em><em> </em><em>by</em><em> </em><em>volcanic</em><em> </em><em>eruptions</em><em> </em><em>attracts</em><em> </em><em>tourists</em><em>. </em>

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It's a distance-time graph showing the speed of an object

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A balloon has a volume of 1.75L at a temperature of 25 °C . what will be the volume of the balloon if you take it out into the w
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Identify the oxidizing agent and the reducing agent in the reaction. 8H +( aq) + Cr 2O 7 2–( aq) + 3SO 3 2–( aq) → 2Cr 3+( aq) +
S_A_V [24]

Answer:

SO₃²⁻ is the reducing agent and Cr₂O₇²⁻ is the oxidizing agent.

Explanation:

Oxidation reaction:

3SO₃²⁻ (aq) + 3H₂O (l) → 3SO₄²⁻ (aq) + 6H⁺ (aq) + 6e⁻                  

Reduction reaction:

Cr₂O₇²⁻ (aq) + 14H⁺ (aq) + 6e⁻ → 2Cr ³⁺ (aq) + 7H₂O (l)

Now, adding the oxidation and the reduction reactions we get the full net reaction:

Cr₂O₇²⁻ (aq) + 3SO₃²⁻ (aq) + 8H⁺ (aq) → 2Cr ³⁺ (aq) + 3SO₄²⁻ (aq) + 4H₂O(l)

Since, the S in SO₃²⁻, present in the +4 oxidation state is oxidized to +6 oxidation state in SO₄²⁻, by the loss of 2e⁻.

<u>Therefore, SO₃²⁻ is the reducing agent. </u>

And, the Cr in Cr₂O₇²⁻, present in the +6 oxidation state is getting reduced to +3 oxidation state, Cr ³⁺, by the gain of 6e⁻.

<u>Therefore, Cr₂O₇²⁻ is the oxidizing agent.</u>

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