Explanation:
the answer and explanation is in the picture
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Answer:
The answer you would be looking for is option A because all of the other options are either false, or beneficial to us, and i took the test. Thanks
Explanation:
According to the task, you are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C
<span>The you go :
</span>

n1 n2 0
-x -x +2x

After that you have to use the formula

Then you have to solve x, and for that you have to use <span>RT/V
And to find total values:</span>

I am absolutely sure that this would be helpful for you.
Answer:
An F1 offspring could produce four types of gametes, RY, Ry, rY, and ry. The F2 generation supports the independent-assortment model and refutes the linkage model.
Explanation:
Answer:
The concentration would be; 0.0038 μgmL
Explanation:
Half life, t1/2 = 68 minutes
Initial Conc. [A]o = 0.12/μgmL
Final Conc [A] = ?
Time. k = 340 minutes
ln[A] = ln[A]o - kt
t1/2 = ln2 / k
k = 0.693 / t1/2 = 0.693 / 68 = 0.01019
ln[A] = ln (0.12) - 0.01019 (340)
ln[A] = -2.1203 -3.4646
ln[A] = -5.5849
[A] = 0.00375 ≈ 0.0038 μgmL