Answer:
5.2g copper (Cu) => 0.082 moles copper (2 sig.figs.)
Explanation:
mole conversions:
grams to moles => divide by formula wt.
moles to grams => multiply by formula wt.
gas volumes to moles => divide volume by 22.4Liters/mole (STP conditions only)
This problem:
mass to moles => divide by formula wt.
mass = 5.2g = 5.2g/63.5g/mole = 0.082 moles copper (2 sig.figs.)
They should identify the confounding variable.
Some condition that is not examined by the scientist might alter the experiment result. That condition is called confounding variable. If the method of the experiment same but result is very different, there should be unidentified confounding variable. It could be air humidity, temperature, ventilation, light, time of the year or anything that might not be seen by naked eye.
Try to redo the experiment with controlling variable as much as possible.
So the unbalanced equation would be Mg + N^2 --> Mg^3N^2
Which means the balanced equation would be 3Mg + N^2 --> Mg^3N^2
This is balance the equation out since you now has 3 magnesium and 2 nitrogen on the left side, and 3 magnesium on 2 nitrogen on the right. Double check my work though, it's been awhile.
Answer:
Volume = 746 L
Explanation:
Given that:- Mass of copper(II) fluoride = 175 g
Molar mass of copper(II) fluoride = 101.543 g/mol
The formula for the calculation of moles is shown below:
Thus,
![Moles_{copper(II)\ fluoride}= 1.7234\ mol](https://tex.z-dn.net/?f=Moles_%7Bcopper%28II%29%5C%20fluoride%7D%3D%201.7234%5C%20mol)
Also,
Considering:
So,,
![Volume =\frac{Moles\ of\ solute}{Molarity}](https://tex.z-dn.net/?f=Volume%20%3D%5Cfrac%7BMoles%5C%20of%5C%20solute%7D%7BMolarity%7D)
Given, Molarity = 0.00231 M
So,
![Volume =\frac{1.7234}{0.00231}\ L](https://tex.z-dn.net/?f=Volume%20%3D%5Cfrac%7B1.7234%7D%7B0.00231%7D%5C%20L)
<u>Volume = 746 L</u>
Beta decay converts a neutron to a proton and emits a high-energy electron, producing a daughter nucleus with the same mass number as the parent and an atomic number that is higher by 1.