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NARA [144]
3 years ago
5

What will be the kinetic energy change of the ram of a pile driver when it suddenly undergoes a 10 kJ decrease in potential ener

gy?
Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:

K.E. increase by 10 KJ.

Explanation:

Total mechanical energy of a system is always constant which is the sum of kinetic and potential energies of the system. So, when the ram of a pile driver when it suddenly undergoes a 10 kJ decrease in potential energy, its kinetic energy must have increase by 10 KJ. So, as to make their sum constant again.

Mechanical energy = Kinetic energy + potential energy = constant

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43. Use Table 3-1 to identify a substance that undergoes a
LuckyWell [14K]

Answer:

Oxygen, and from solid to liquid. This is because oxygen's melting point is at -218°C. Melting point refers to the temperature where heat causes particles to vibrate with sufficient energy to break the solid structure, so for oxygen this means it's being turned into a liquid.

4 0
3 years ago
Which subatomic particle plays the greatest part in determining the properties of and element?
alexandr1967 [171]
There are three subatomic particle that are present in an atom. These are electrons, protons, and neutrons. Among these three, I believe the <span>subatomic particle that plays the greatest part in determining the properties of and element would be the electron. It is what determines how the element would react in different conditions.</span>
3 0
3 years ago
Somebody please answer
Zepler [3.9K]

Answer:

177 mmHg

Explanation:

Given that:

The sample of  a gas is with Pressure (1) P_1 = 500 mmHg

The initial temperature T_1 = 773 K

The final temperature T_2 = 273 K

Using ideal gas equation:

\dfrac{P_1}{T_1} = \dfrac{P_2}{T_2} \\ \\  \dfrac{500}{773} = \dfrac{P_2}{273} \\ \\  (136500) = 773 \times P_2 \\ \\ P_2 = \dfrac{136500}{773} \\ \\  P_2 = 176.58 \ mmHg \\ \\  \simeq 177 mmHg

7 0
3 years ago
The standard free energy of activation of a reaction A is 81.9 kJ mol–1 (19.6 kcal mol–1) at 298 K. Reaction B is one million ti
klasskru [66]

Answer:

54.9 kJ/mol

Explanation:

The relation between the activation energy (Ea) and the rate constant (k) is given by the Arrhenius equation.

k=A.e^{-Ea/RT}

where,

A is a collision factor

R is the ideal gas constant

T is the absolute temperature

Reaction B is one million times faster than reaction A at the same temperature. So k_{B}=10^{6} k_{A}.

Then,

k_{B}=10^{6} k_{A}\\A.e^{-Ea_{B}/RT}=10^{6}A.e^{-Ea_{A}/RT}\\e^{-Ea_{B}/RT}=10^{6}e^{-Ea_{A}/RT}\\ln(e^{-Ea_{B}/RT})=ln(10^{6}e^{-Ea_{A}/RT})\\\frac{-Ea_{B}}{RT} =ln10^{6} -\frac{Ea_{A}}{RT} \\Ea_{B}=(ln10^{6} -\frac{Ea_{A}}{RT}).(-RT)=(ln10^{6}-\frac{89.1kJ/mol}{(8.314\times 10^{-3} kJ/mol.K).298K} ).(-8.314\times 10^{-3} \frac{kJ}{mol.K}.298K )=54.9kJ/mol

8 0
3 years ago
The mathematical relationship between gas solubility and pressure is called Henry's Law, solubility = kHPgas where kH is the Hen
Diano4ka-milaya [45]

Answer : The unit of k_H in mol/L.mm Hg is, 1.8\times 10^{-6}mol/L.mmHg

Explanation :

As we know that the k_H is the Henry's Law constant for argon at 25^oC is, 1.4\times 10^{-3}mol/L.atm

Now we have to determine the unit of k_H in mol/L.mm Hg

Conversion used for pressure from atm to mmHg is:

1 atm = 760 mmHg

So,

k_H=1.4\times 10^{-3}mol/L.atm\times \frac{1atm}{760mmHg}

k_H=1.8\times 10^{-6}mol/L.mmHg

Thus, the unit of k_H in mol/L.mm Hg is, 1.8\times 10^{-6}mol/L.mmHg

5 0
3 years ago
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