Which of the following correctly classifies the number -5 to all of the number sets in which it belongs?
1 answer:
<h3>Answer: Choice C) Real, Rational</h3>
=============================================
Explanation:
Any number you'll encounter so far in your math course will be a real number. This is until you get to something like which is a complex number, but your teacher may not have covered that chapter yet.
Anyways, -5 is a real number because we aren't taking the square root of a negative or anything like that.
-5 is also an integer, but that choice isn't listed. The set of integers is any positive or negative whole numbers, including 0 as well.
Furthermore, -5 is considered rational because -5 = -5/1. We can write -5 as a fraction of two integers where 0 is not in the denominator. With -5 being rational, it cannot be irrational. The term "irrational" means "not rational".
You might be interested in
<h3>Answer: C) 6</h3>
====================================================
Explanation:
The weird looking E symbol is the greek uppercase letter sigma. It refers to a sum.
It tells us to add up terms in the form (-1)^n*(3n+2) where n is an integer ranging from n = 1 to n = 4.
------------------
If n = 1, then we have
(-1)^n*(3n+2) = (-1)^1*(3*1+2) = -5
Let A = -5 as we'll use it later.
------------------
If n = 2, then
(-1)^n*(3n+2) = (-1)^2*(3*2+2) = 8
Let B = 8 since we'll use this later as well
------------------
If n = 3, then
(-1)^n*(3n+2) = (-1)^3*(3*3+2) = -11
Let C = -11
-------------------
If n = 4, then
(-1)^n*(3n+2) = (-1)^4*(3*4+2) = 14
Let D = 14.
--------------------
We'll add up the values of A,B,C,D to get the final answer
A+B+C+D = -5+8+(-11)+14 = 6
This means that