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PilotLPTM [1.2K]

3 years ago

13

A teacher wrote the following part of a balanced chemical equation: Cu+2AgNO 3 To show the conservation of matter in the chemica

l reaction , how many silver (Ag) atoms will be needed on the right-hand side of the balanced equation ?

2 answers:

Crazy boy [7]3 years ago

8 0

Answer:

2

Explanation:

AP3X

Llana [10]3 years ago

7 0

2, because there are 2 silver atoms on the left

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Ethane, C2H6, burns in oxygen. First write a balanced equation for this combustion reaction. What mass of oxygen, in grams, is r

iren [92.7K]

Answer:

We need 50.6 grams of oxygen

Explanation:

Step 1: Data given

Mass of ethane = 13.6 grams

Molar mass of ethane = 30.07 g/mol

Step 2: The balanced equation

2C2H6 + 7O2 → 4CO2 + 6H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 13.6 grams / 30.07 g/mol

Moles ethane = 0.452 moles

Step 4: Calculate moles oxygen

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

For 0.452 moles ethane we need 3.5*0.452 = 1.582 moles O2

Step 5: Calculate mass O2

Mass O2 = moles O2 * molar mass O2

Mass O2 = 1.582 moles * 32.0 g/mol

Mass O2 = 50.6 grams

We need 50.6 grams of oxygen

7 0

3 years ago

List the procedural steps, from start to finish, that are required to convert 2‑naphthol and allyl bromide into allyl 2‑naphthyl

elena-14-01-66 [18.8K]

<h3>Procedural steps are: - </h3>

On a small scale, the reaction is carried out by combining the alcohol, the haloalkane, and the phase transfer catalyst in a conical vial.
To start the reaction, sodium hydoxide (base) is added.
To prevent solvent evaporation, the reaction flask is covered and stirred during the reaction.
TLC monitors the reaction's progress to ensure that no time is wasted.
To remove any remaining water, the reaction solution is dried over calcium chloride.
Column chromatography is used to purify the product, and evaporation is used to collect it.

<h3>What is Catalysis?</h3>

Catalysis is the process of boosting the pace of a chemical reaction by using a catalyst. Catalysts are not consumed in the reaction and so survive it.

To learn more about catalysis from the given link

brainly.com/question/1372992

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1 year ago

Claudia performed a flame test in her lab. The result of her flame test is shown here.

Masteriza [31]

Answer:

Where is the results and what is the question or is there a picture

Explanation:

6 0

3 years ago

Read 2 more answers

0.0009547863= x^-1.644

Andrej [43]

Answer: 68.71317831

Explanation:

5 0

3 years ago

A compound is made up of 28 g N, 24 g C, 48 g O, and 8 g H .What is the empirical formula?

vovikov84 [41]

Answer:

$\rm C_2H_8N_2O_3$ .

Explanation:

<h3>Step One: calculate the coefficients. </h3>

Look up the relative atomic mass of these four elements on a modern periodic table:

$\rm C$ : approximately $12$ .
$\rm H$ : approximately $1$ .
$\rm N$ : approximately $14$ .
$\rm O$ : approximately $16$ .

The relative atomic mass of an element is numerically equal to the mass (in grams, $\rm g$ ,) of one mole of atoms of this element.

For example, the relative atomic mass of $\rm C$ is approximately $12$ . Therefore, each mole of $\rm C\!$ atoms would have a mass of $12\; \rm g$ .

This sample contains $24\; \rm g$ of carbon. That would correspond to approximately $\displaystyle \left(\frac{24}{12}\right)\; \rm mol = 2\; \rm mol$ of $\rm C$ atoms.

Similarly, for the other three elements:

$\displaystyle n(\mathrm{H}) \approx \frac{8\; \rm g}{1\; \rm g \cdot mol^{-1}} = 8\; \rm mol$ .

$\displaystyle n(\mathrm{N}) \approx \frac{28\; \rm g}{14\; \rm g \cdot mol^{-1}} = 2\; \rm mol$ .

$\displaystyle n(\mathrm{O}) \approx \frac{48\; \rm g}{16\; \rm g \cdot mol^{-1}} = 3\; \rm mol$ .

Hence, the ratio between these elements in this compound would be:

$n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3$ .

In the empirical formula of a compound, the coefficients should represent the smallest possible integer ratio between the number of atoms of these elements.

$n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3$ is indeed the smallest possible integer ratio between the number of atoms of these elements.

<h3>Step Two: arrange the elements in an appropriate order</h3>

Apply the Hill System to arrange these four elements in the empirical formula. In the Hill System:

If carbon, $\rm C$ , is present in this compound, then:

$\rm C$ (carbon) and then $\rm H$ (hydrogen) will be the first two elements listed in the formula (ignore the hydrogen if it is not in the compound.)
The other elements in this compound will be listed in alphabetical order.

If there is no carbon $\rm C$ in this compound, then list all the elements in this compound in alphabetical order.

Both $\rm C$ (carbon) and $\rm H$ (hydrogen) are found in this compound. Therefore, the first element in the list would be $\rm C\!$ . The second would be $\rm H\!$ , followed by $\rm N\!$ and then $\rm O\!$ .

Hence, the empirical formula of this compound would be $\rm C_2H_8N_2O_3$ .

6 0

3 years ago