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Alina [70]
3 years ago
8

There are 3 paper clips and 5 erasers in a paper sack. If 2 items are drawn at random, without replacement, what is the probabil

ity that one will draw a paper clip and then an eraser?
Mathematics
1 answer:
Mkey [24]3 years ago
7 0

Answer:

15/56

Step-by-step explanation:

Probability of picking out a paperclip first is 3/8, then the probability of picking out an eraser is 5/7. Multiply these probabilities (15/56)

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Use the distributive property to find the equivalent expression. 9(2 + 3x) =
allochka39001 [22]

Answer:

9(2+3x)

9*2+9*3x

18+27x

Step-by-step explanation:

6 0
3 years ago
Determine the first five terms of each geometric sequence.<br><br> a1= 5<br><br> r = 0.5
mafiozo [28]
AN = (1/2^N-1) A1 { in general AN= (r^N-1) A1 

<span>A5 = (1/2^4) 40 = 40/16 = 0.5
</span>
So the answer to your question is 0.5
6 0
4 years ago
The price of a flight was increased by 3% to £650. What was the price before the increase? Give your answer to the nearest penny
kramer

Answer:

269

Step-by-step explanation:

4 0
3 years ago
In a survey, 11 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped
pickupchik [31]

Answer:

The population standard deviation is not known.

90% Confidence interval by T₁₀-distribution: (38.3, 53.7).

Step-by-step explanation:

The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus 11 - 1 = 10.

Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,

  • The area to the left of the lower end of the interval shall be 1/2 \cdot (1 - 0.90)= 0.05.
  • The area to the left of the upper end of the interval shall be 0.05 + 0.90 = 0.95.

Look up the t-score of the upper end on an inverse t-table. Focus on the entry with

  • a degree of freedom of 10, and
  • a cumulative probability of 0.95.

t \approx 1.812.

This value can also be found with technology.

The formula for 1/2 the width of a confidence interval where standard deviation is unknown (only an estimate) is:

\displaystyle t \cdot \frac{s_{n-1}}{\sqrt{n}},

where

  • t is the t-score at the upper end of the interval,
  • s_{n-1} is the unbiased estimate for the standard deviation, and
  • n is the sample size.

For this confidence interval:

  • t \approx 1.812,
  • s_{n-1} = 14, and
  • n = 11.

Hence the width of the 90% confidence interval is

\displaystyle 1.812 \times \frac{14}{\sqrt{10}} \approx 7.65.

The confidence interval is centered at the unbiased estimate of the population mean. The 90% confidence interval will be approximately:

(38.3, 53.7).

5 0
3 years ago
ASAP what is the value of k?<br> -3(k+7) - 5k+4=23
Maru [420]

Answer:

k=−5

Step-by-step explanation:

−3(k+7)−5k+4=23

(−3)(k)+(−3)(7)+−5k+4=23(Distribute)

−3k+−21+−5k+4=23

(−3k+−5k)+(−21+4)=23(Combine Like Terms)

−8k+−17=23

−8k−17=23

Step 2: Add 17 to both sides.

−8k−17+17=23+17

−8k=40

Step 3: Divide both sides by -8.

−8k

−8

=

40

−8

k=−5

Answer:

k=−5

 

6 0
3 years ago
Read 2 more answers
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