Answer:
9(2+3x)
9*2+9*3x
18+27x
Step-by-step explanation:
AN = (1/2^N-1) A1 { in general AN= (r^N-1) A1
<span>A5 = (1/2^4) 40 = 40/16 = 0.5
</span>
So the answer to your question is 0.5
Answer:
The population standard deviation is not known.
90% Confidence interval by T₁₀-distribution: (38.3, 53.7).
Step-by-step explanation:
The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus
.
Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,
- The area to the left of the lower end of the interval shall be
. - The area to the left of the upper end of the interval shall be
.
Look up the t-score of the upper end on an inverse t-table. Focus on the entry with
- a degree of freedom of 10, and
- a cumulative probability of 0.95.
.
This value can also be found with technology.
The formula for 1/2 the width of a confidence interval where standard deviation is unknown (only an estimate) is:
,
where
is the t-score at the upper end of the interval,
is the unbiased estimate for the standard deviation, and
is the sample size.
For this confidence interval:
Hence the width of the 90% confidence interval is
.
The confidence interval is centered at the unbiased estimate of the population mean. The 90% confidence interval will be approximately:
.
Answer:
k=−5
Step-by-step explanation:
−3(k+7)−5k+4=23
(−3)(k)+(−3)(7)+−5k+4=23(Distribute)
−3k+−21+−5k+4=23
(−3k+−5k)+(−21+4)=23(Combine Like Terms)
−8k+−17=23
−8k−17=23
Step 2: Add 17 to both sides.
−8k−17+17=23+17
−8k=40
Step 3: Divide both sides by -8.
−8k
−8
=
40
−8
k=−5
Answer:
k=−5