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Komok [63]
3 years ago
12

Please Help!!!!! According to the graph which figure shows the average speed of the horse that won the race

Physics
1 answer:
Vikentia [17]3 years ago
5 0

Average speed will be given by

v_{avg} = \frac{total distance}{total time}

here from graph we know that

total distance = 300 m

total time taken = 15 s

now from above equation we know that

v_{avg} = \frac{300 m}{15 s}

v_{avg} = 20 m/s

so average speed will be 20 m/s

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Y=k/x, x is halved.<br> what happens to the value of y
IgorLugansk [536]

Answer:

y is doubled

Explanation:

If x is halved, that means the value is doubled. Here is an exmaple:

y=1/2. If the denominater is doubled, y would equal y=1/1. So, the value of y has doubled from 0.5 to 1. Therefore, if the denominator is halved, the solution will be doubled.

8 0
3 years ago
Dinitrogen oxide has?
Vesnalui [34]
Two atoms of the element bind to form dinitrogen and it’s a colourless and odorless diatomic gas with the formula N2. Also Dinitrogen forms up about 78% of earths atmosphere
3 0
3 years ago
An elevator filled with passengers has a mass of 1683 kg. (a) The elevator accelerates upward from rest at a rate of 1.20 m/s2 f
artcher [175]

Answer:

the tension is 18513N

Explanation:

Given that

mass = 1683kg

acceleration = 1.2m/s^2

acceleration due to gravity = 9.8m/s^2

T-mg =   ma

T = ma + mg

T = m(a +g)

T = 1683 kg(1.20 m/s2 + 9.8)

T = 1683 (11)

T = 18513N

therefore, the tension is 18513N

4 0
3 years ago
Read 2 more answers
what is the maximum speed of a 34-g object bouncing on a spring (k=78.1 N/m) with an amplitude of 3.5-cm?
Vika [28.1K]

Answer:

The maximum speed of the mass is 1.67 m/s.  

Explanation:

We have,

Mass of object is 34 g or 0.034 kg

Spring constant of the spring is 78.1 N/m

Amplitude attained by the object is 3.5 cm or 0.035 m

It is required to find the maximum speed of the object in this spring mass system. The maximum speed is given by :

v=A\omega

\omega=\sqrt{\dfrac{k}{m}}

v=A\sqrt{\dfrac{k}{m}}

Plugging all the values in above formula,

v=0.035\times \sqrt{\dfrac{78.1}{0.034}}\\\\v=1.67\ m/s

So, the maximum speed of the mass is 1.67 m/s.  

4 0
3 years ago
The launch velocity of a toy car launcher is determined to be 5 m/s. If the car is to be launched from a height of 0.5 m, where
lora16 [44]

Answer:

1.6 m

Explanation:

Given that the launch velocity of a toy car launcher is determined to be 5 m/s. If the car is to be launched from a height of 0.5 m.

The time for landing should be calculated by using the second equation of motion formula

h = Ut + 1/2gt^2

Let U = 0

0.5 = 1/2 × 9.8 × t^2

0.5 = 4.9t^2

t^2 = 0.5 / 4.9

t^2 = 0.102

t = 0.32 s

The target should be placed so that the toy car lands on it at:

Distance = 5 × 0.32

distance = 1.597 m

Distance = 1.6 m

Therefore, the target should be placed so that the toy car lands on it 1.6 metres away.

7 0
3 years ago
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