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8090 [49]
2 years ago
6

If Frequency F, velocity v, and density D are considered fundamental units, the dimensional formula for momentum will be :

Physics
2 answers:
rewona [7]2 years ago
7 0

Answer:

<u>(Frequency)⁻³(velocity)⁴Density</u>

Explanation:

See attachments.

gizmo_the_mogwai [7]2 years ago
5 0

Let's see

Momentum be P

\\ \rm\Rrightarrow P=[Frequency]^a[velocity]^b[Density]^c

\\ \rm\Rrightarrow [P]=[F]^a[v]^b[D]^c

\\ \rm\Rrightarrow [M^1L^1T^{-1}]=[T^{-1}]^a[L^1T^{-1}]^b[M^1L^{-3}]^c

\\ \rm\Rrightarrow MLT^{-1}=T^{-a}L^bT^{-b}M^cL^{-3c}

\\ \rm\Rrightarrow MLT^{-1}=T^{-a-b}L^{b-3c}M^c

On comaparing

  • c=1

So

  • b-3c=1
  • b-3=1
  • b=1+3
  • b=4

and

  • -a-b=-1
  • -a-4=-1
  • -a=-1+4=3
  • a=-3

So the unit is

  • DV⁴/F³
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