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3 years ago

what is the maximum speed of a 34-g object bouncing on a spring (k=78.1 N/m) with an amplitude of 3.5-cm?

Physics

1 answer:

Vika [28.1K]3 years ago

4 0

Answer:

The maximum speed of the mass is 1.67 m/s.

Explanation:

We have,

Mass of object is 34 g or 0.034 kg

Spring constant of the spring is 78.1 N/m

Amplitude attained by the object is 3.5 cm or 0.035 m

It is required to find the maximum speed of the object in this spring mass system. The maximum speed is given by :

$v=A\omega$

$\omega=\sqrt{\dfrac{k}{m}}$

$v=A\sqrt{\dfrac{k}{m}}$

Plugging all the values in above formula,

$v=0.035\times \sqrt{\dfrac{78.1}{0.034}}\\\\v=1.67\ m/s$

So, the maximum speed of the mass is 1.67 m/s.

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Answer:

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Explanation:

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Answer:

The reason that it takes longer to get the water to boiling temperature than it is to cool it down again is because heating in the most simple sense is inefficient and will cause a lot if energy lost while cooling is to be turn's into quite a efficient process.

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2 years ago

If an object is thrown upward with an initial velocity of 128 ft/second, then its height after t seconds is given by the follow

IrinaK [193]

Answer:

The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.

Explanation:

Given that,

Initial velocity u= 128 ft/sec

Equation of height

$h = 128t-32t^2$ ....(I)

(a). We need to calculate the maximum height

Firstly we need to calculate the time

$\dfrac{dh}{dt}=0$

From equation (I)

$\dfrac{dh}{dt}=128-64t$

$128-64t=0$

$t=\dfrac{128}{64}$

$t=2\ sec$

Now, for maximum height

Put the value of t in equation (I)

$h =128\times2-32\times4$

$h=128\ ft$

(b). The number of seconds it takes the object to hit the ground.

We know that, when the object reaches ground the height becomes zero

$128t-32t^2=0$

$t(128-32t)=0$

$128=32t$

$t=4\ sec$

Hence, The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.

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3 years ago

Calculate the work done by a force of 30 N in lifting a load of 2 kg to a height of 10 m (g = 10 m/s2)

Mars2501 [29]

Answer:

300 J

Explanation:

Given :

Applied force = 30 N
Mass = 2 kg
Height = 10 m
g = 10 m/s²

Work done by the force :

Work done = Force x Displacement
Work done = mg x h
Work done = 30 N x 10 m
Work done = 300 J

Note :

What you have calculated is the work done by gravitational force on the object (that too, incorrectly)
But in the end, it asks for work done by the force of 30N
Hence, the given answer ~

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2 years ago

What type of modulation is typically used by broadcasting stations to transmit pictures on television screens?

umka21 [38]

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3 years ago

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