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Rainbow [258]
3 years ago
9

The reaction between lead metal and dilute hydrochloric acid stops immediately explanation ​

Chemistry
1 answer:
sesenic [268]3 years ago
3 0

Answer:

The metal responds in a certain way with dilute HCl to give it's corresponding chloride and hydrogen gas is liberated.

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How much space does a 246g box take up. Its density is listed at 3.2 g/cm3.
CaHeK987 [17]

Answer:

76.875 cm3

<h2>Explanation:</h2>

Since: Density = \frac{Mass}{volume\\}

Then: Volume = \frac{Mass}{Density\\}

The mass of the box = 246g

and the density = 3.2 g/cm3

Then: The volume = \frac{246}{3.2}

= 76.875 cm3

4 0
3 years ago
Which protists lack cilia and flagella, but can still move around?
timama [110]

Answer: amoebae !

Explanation:

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To explain the photoelectric effect, Albert Einstein linked the photoelectric effect to an idea from which scientist?
blondinia [14]
Based upon Max Planck's theory of black-body radiation, Einstein theorized that the energy in each quantum of light was equal to the frequency multiplied by a constant, later called Planck's constant. A photon above a threshold frequency has the required energy to eject a single electron, creating the observed effect.
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Please please help me with this chemistry question over limiting reactants it’s due by midnight! I’ll mark you BRAINIEST!!!
OverLord2011 [107]

Answer: 1.5 moles

Explanation: one mole Zn uses 2 moles HCl.

1.5 moles Zn uses 3.0 mol HCl. Then Zn is a limiting reactant

And produces equal amount of H2.

4 0
3 years ago
An 80L capacity steel cylinder contains H2 at a pressure of 110 atm and 30 ° C, after extracting a certain amount of gas, the pr
icang [17]

Answer:

2200 L

Explanation:

Ideal gas law:

PV = nRT,

where P is absolute pressure,

V is volume,

n is number of moles,

R is universal gas constant,

and T is absolute temperature.

The initial number of moles is:

(110 atm) (80 L) = n (0.0821 L atm / K / mol) (30 + 273.15) K

n = 353.58 mol

After some gas is removed, the number of moles remaining is:

(80 atm) (80 L) = n (0.0821 L atm / K / mol) (30 + 273.15) K

n = 257.15 mol

The amount of gas removed is therefore:

n = 353.58 mol − 257.15 mol

n = 92.43 mol

At normal conditions, the volume of this gas is:

PV = nRT

(1 atm) V = (92.43 mol) (0.0821 L atm / K / mol) (273.15 K)

V = 2162.5 L

Rounded, the volume is approximately 2200 liters.

4 0
3 years ago
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