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iogann1982 [59]
3 years ago
7

When the same amount of heat is added to 50.0 g of each substance, which of the following will have the smallest temperature inc

rease?

Physics
1 answer:
vitfil [10]3 years ago
5 0

Answer:

Aluminium

Explanation:

When a certain amount of heat is supplied to a substance, the temperature of the substance increases according to the equation:

\Delta T = \frac{Q}{mC}

where

\Delta T is the increase in temperature

Q is the amount of heat supplied to the substance

m is the mass of the substance

C is the specific heat capacity of the substance

Here the four substances have the same mass,

m = 50.0 g

Also, the amount of heat supplied to the 4 substances is the same. This means that their increase in temperature is inversely proportional to their specific heat capacity:

\Delta T \propto \frac{1}{C}

Therefore, the substance with the highest specific heat capacity will have the smallest temperature increase: by comparing the values in the table, we see that alluminium has the highest specific heat capacity (0.90 J/gC), therefore it will have the smallest temperature increase.

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F = m*a, mass times acceleration.

F = 15*10 = 150 N
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When bitten by an animal, one should:
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Una persona cierra una puerta de 1 metro de ancho aplicando una fuerza de 40 [N], perpendicular a ella, a 90 [cm] de su eje de r
Damm [24]

Answer:

El módulo del torque aplicado es 36 Nm

Explanation:

En los movimientos rotatorios, la cantidad de fuerza aplicada no depende de la acción gravitacional sino del momento inercial, que es el equivalente angular de la inercia (masa) y representa la resistencia que un objeto ofrece al rotar alrededor de su eje. Cuando un cuerpo rígido rota alrededor de su eje debe considerarse , además de la masa, el radio de giro ya que estos dos factores determinan la resistencia del cuerpo a los cambios de movimiento rotatorio a través de un eje determinado.

De esta manera, se llama torque o momento de una fuerza a la capacidad de dicha fuerza para producir un giro o rotación alrededor de un punto.

En muchas ocasiones el punto de aplicación de la fuerza no coincide con el punto de aplicación en el cuerpo. En este caso la fuerza actúa sobre el objeto y su estructura a cierta distancia, mediante un  elemento que traslada esa acción de esta fuerza hasta el objeto. Entonces, el momento de una fuerza  es, matemáticamente,  igual al producto de la intensidad de la fuerza (módulo) por la distancia desde el punto de aplicación de la fuerza hasta el eje de giro:

M=F*d*sen θ

donde F es la fuerza en Newton (N), d la distancia en metros (m), θ el ángulo que forma la fuerza con el objeto al cual se le aplica la fuerza y M el momento, que se mide en Newton por metro (Nm).

En este caso:

  • F= 40 N
  • d= 90 cm= 0.9 m (siendo 100 cm= 1 m)
  • θ= 90° ya que la fuerza se aplica de forma perpendicular. Entonces sen θ= sen 90= 1

Reemplazando:

M=40 N*0.9 m* 1

Resolviendo:

M= 36 Nm

<u><em>El módulo del torque aplicado es 36 Nm</em></u>

3 0
3 years ago
A 0.2-stone is attached to a string and swung in a circle of radius 0.6 m on a horizontal and frictionless surface. If the stone
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Answer:

2960 N

Explanation:

Convert rev/min to rad/s:

150 rev/min × (2π rad/rev) × (1 min / 60 s) = 50π rad/s

Sum of forces in the centripetal direction:

∑F = ma

T = m v² / r

T = m ω² r

T = (0.2 kg) (50π rad/s)² (0.6 m)

T = 2960 N

3 0
3 years ago
A potentiometer wire of length 1m and resistance 2Ω is connected in series with a variable resistance and 2V accumulator of negl
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Answer:

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Explanation:

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