Complete Question
The complete question is shown on the first uploaded image
Answer:
a) 58 Hz b) 7.73 mV
Explanation:
From the complete question we are given that
Radius of the semi circle , a = 3.0 cm = (3.0)(1 × m/1 cm)
=3.0 × m
Angular speed ,w = 58 rev/s
= (58 rev/s)(2π rad /1 rev)
= 364.4 rad/s
Magnetic field, B = 15 mT
= (15 mT)(1 × T/ 1 mT)
= 15 × T
a) f = 58 rev/s
= 58 Hz
b) The Induced emf, ∈ = ω<em>Bπ</em> /2
= T)(π)(3.0 × m)^2)÷2[/tex]
= 0.007728 V
= 7.73 mV
Answer:
Explanation:
The kinematic equation
gives the final velocity of the object given the initial velocity , the acceleration , and the distance traveled .
For our case, the object is dropped; therefore,
I.e. the initial velocity is zero. The acceleration due to gravity is
,
and the distance traveled is .
Putting the values into the equation we get:
The final velocity of the object is 44.27 m/s.
We are given with
distance traveled through vacuum = 1.0 m
refractive index of water = 1.33
refractive index of glass = 1.50
refractive index of diamond = 2.42
distance traveled through water is = 1.0/1.33 = 0.75 m
distance traveled through water is = 1.0/1.50 = 0.67 m
distance traveled through water is = 1.0/2.42 = 0.41 m
I believe that B is the answer.
Answer:
The potential energy of a 2 kg mass at a height of 40 meters is 784 J
Explanation:
Potential energy is that energy that a body possesses due to the height at which it is located and whose unit of measurement of the International System of Units is the joule (J).
The potential energy of a body is the result of multiplying its mass by its height and by gravity:
Ep=m*g*h
Potential energy Ep, is measured in joules (J), mass m is measured in kilograms (kg), gravity, g, in meters / second-squared (), and height, h , in meters (m).
In this case:
- Ep=?
- m= 2 kg
- g= 9.8
- h= 40 m
Replacing:
Ep= 2 kg* 9.8 * 40 m
Solving:
Ep= 784 J
<u><em>The potential energy of a 2 kg mass at a height of 40 meters is 784 J</em></u>