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SVEN [57.7K]
3 years ago
5

Two particles of equal mass m are at the vertices of the base of an equilateral triangle. The triangle’s center of mass is midwa

y between the base and the third vertex. What’s the mass at the third vertex?

Physics
1 answer:
Helga [31]3 years ago
8 0

Answer:Twice of given mass

Explanation:

Given

Two Particles of Equal mass placed at the base of an equilateral Triangle

let mass of two equal masses be m and third mass be m'

Taking one of the masses at origin

Therefore co-ordinates of first mass be (0,0)

Co-ordinates of other equal mass is (a,0)

if a is the length of triangle

co-ordinates of final mass (\frac{a}{2},\frac{\sqrt{3}a}{2})

Given its center of mass is at midway between base and third vertex therefore

x_{cm},y_{cm}=\frac{a}{2},\frac{\sqrt{3}a}{4}

y_{cm}=\frac{m_1y_1+m_2y_2+m_3y_3}{m_1+m_2+m_3}

\frac{\sqrt{3}a}{4}=\frac{m\cdot 0+m\cdot 0+m'\cdot \frac{\sqrt{3}a}{2}}{m+m+m'}

2m+m'=4\times (\frac{m'}{2})

2m+m'=2m'

m'=2m

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Gold has a specific heat of 0.130 J/g*C. If 195 joules of heat are added to 15 grams of gold how much does the temperature of th
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The correct answer to the question is :  100\ ^0C

EXPLANATION :

As per the question, the specific heat of gold is given as c = 0.130\ J/g^0C

The heat given to the gold dQ = 195 J

The mass of the gold is given as m = 15 gram.

We are asked to calculate the change in temperature.

Let the change in temperature is dT.

We know that dQ = mcdT

                      dT=\ \frac{dQ}{mc}

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                             =\ 100\ ^0C                   [ANS]

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You are discussing a material that has a strong resistance to the flow of electrons. This is a description of a(n)
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3 years ago
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Look at the graph
viva [34]
Here, Carefully look at the graph.
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Hope this helps!
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