Answer:
116 N.
Explanation:
Given,
mass of the ball, m = 0.145 Kg
initial speed = 0 m/s
Final speed = 40 m/s
time = 50 ms = 0.05 s
Force is equal to change in momentum per unit time


F = 116 N
Force of the pitcher hand on the ball is equal to 116 N.
Answer:
Explanation:
<u>Given the following data;</u>
Initial velocity = 0 (since the stone is starting from rest).
Final velocity = 32 m/s
Acceleration = g = 10 m/s²
Time = 3.2 seconds
To show that the speed of the stone when it hits the ground is 32 m/s, we would use the first equation of motion;
Where;
- V is the final velocity.
- U is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
Substituting into the formula, we have;

<em>Proven: 32 m/s = 32 m/s</em>
Answer:
Explanation:
We shall apply Gauss's Law to find the solution .
flux entering the cube = E X A
= 46.8 X 147.1 X 147.1 Weber
flux going out of cube
= 114 x 147.1 X 147.1 Weber
Net flux going out
= ( 114 x 147.1 X 147.1 - 46.8 X 147.1 X 147.1 )
= 1454101.15 weber .
according to Gauss's law
q / ε₀ = 1.4541 x 10⁶ , q is required charge inside the cube.
q = 8.85 x 10⁻¹² x 1.4541 x 10⁶
= 12.868 x 10⁻⁶ C
= 12.868 μC.
Distance is 50 km
Displacement is 10 km
<u>Explanation:</u>
Given:
Distance toward south, x = 25 km
Distance towards west, y = 10 km
Distance towards north, z = 15 km
(a) Total distance, D = ?
Total distance, D = x + y + z
D = 25 + 10 + 15
D = 50km
(b) Displacement, d = ?
Displacement = final position - initial position
= 10 - 0 km
= 10km
Answer:
Final speed of the ball = Vf= 12.52 m/s when it hits the ground
Explanation:
Height = S= 8.0 m
Initial Velocity= Vi = 0 m/s
Final Velocity= Vf =?
Acceleration due to gravity= a=9.8m/s²
Using Newtons third equation of motion
2as= Vf²- Vi²
2(9.8) 8= Vf²- 0
156.8= Vf²
Vf=√156.8= 12.52m/s
Final Speed of the ball is 12.52 m/s