The volume that sulfur dioxide will occupy with a volume of 652 mL at 40.0°C and 0.75 atm is 0.019moles. Details about volume can be found below.
<h3>How to calculate volume?</h3>
The volume of a gas can be calculated using the following formula:
PV = nRT
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
0.75 × 0.652 = n × 0.0821 × 313
0.489 = 25.69n
n = 0.489/25.69
n = 0.019moles
Therefore, the volume that sulfur dioxide will occupy with a volume of 652 mL at 40.0°C and 0.75 atm is 0.019moles.
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<u>Answer:</u> The mass of water that should be added in 203.07 grams
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:
Where,
m = molality of barium iodide solution = 0.175 m
= Given mass of solute (barium iodide) = 13.9 g
= Molar mass of solute (barium iodide) = 391.14 g/mol
= Mass of solvent (water) = ? g
Putting values in above equation, we get:
Hence, the mass of water that should be added in 203.07 grams
Answer:
Mark me brainlist I will then answer in comment
3.4 X 10^-2 because you start your equation with 2.5g in your (what we call train tracks). Then you have to find the GFM (gram formula mass) of KCl (potassium chloride). You find this by adding the average atomic mass of each element. Potassium's is 39.10 and Chlorine's is 35.45 which gives you a total of 74.55 grams per mol. so now that you have found the GFM you plug that number into the diagonal bottom in order to cancel the gram units. Then you would place 1 mol KCl on top because that is the unit you want. Finally you will divide your original 2.5 by the GFM of 74.55 to get an answer of 0.033534 mol KCl... but since sig figs matter your final answer will be 3.4 X 10^-2
They have different amounts of protons, therefore, making them completely different elements.
