There are 6.022 × 10²³ atoms in 39.948 g of argon and 4.0026 g of helium.
Explanation:
39.945 g/mole is the molar mass of argon so 39.948 g of argon are equal to 1 mole of argon.
4.0026 g/mole is the molar mass of helium so 4.0026 g of helium are equal to 1 mole of helium.
We know that Avogadro's number tell us the number of particles in 1 mole of substance which is 6.022 × 10²³.
So in 39.948 g of argon and 4.0026 g of helium contains the same number of atoms, 6.022 × 10²³.
Learn more about:
Avogadro's number
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Answer:
(B) Neutralization...........,
Explanation:-
Neutralisation involves an acid reacting with a base or an alkali, forming a salt and water.
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Answer:
Moles of NO = 0.18
Moles of Br2 = 0.18
Explanation:
The given reaction with ICE table is:
![2NOBr(g)\rightarrow 2NO(g)+Br_{2}(g)](https://tex.z-dn.net/?f=2NOBr%28g%29%5Crightarrow%202NO%28g%29%2BBr_%7B2%7D%28g%29)
Initial 0.64 - -
Change -2x +2x +x
Equilb (0.64-2x) 2x 2x
At equilibrium:
[NOBr] = 0.64-2x
NO = Br2 = 2x
The equilibrium moles of NOBr = 0.46
![i.e.\ 0.64-2x = 0.46\\x = 0.09\ mols](https://tex.z-dn.net/?f=i.e.%5C%20%200.64-2x%20%3D%200.46%5C%5Cx%20%3D%200.09%5C%20mols)
Moles of NO = Moles of Br2 = 2x = 2(0.09) = 0.18 moles