Question

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Answer 1

Answer:

15.2 g of KCl

First option

Explanation:

Decomposition reaction is: 2KClO₃ → 2KCl + 3O₂

We need to convert the mass of chlorate to moles:

25 g / 122.55 g/mol = 0.204 moles

Ratio is  2:2.

Therefore 0.204 moles of chlorate will produce the same amount of chloride. We finally produce 0.204 of KCl

We convert the moles to mass → 0.204 mol . 74.55 g / 1 mol = 15.2 g of KCl