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3 years ago

10

Algebraically prove identities involving the exclusive-OR operation: (a) x ⊕ 0 = x (b) x ⊕ 1 = x′ (c) x ⊕ x = 0 (d) x ⊕ x′ = 1 (

e) x ⊕ y = y ⊕ x (f ) (x ⊕ y) ⊕ z = x ⊕ (y ⊕ z) (g) (x ⊕ y)′ = x′ ⊕ y = x ⊕ y′

1 answer:

zubka84 [21]3 years ago

3 0

Answer:

Explanation:

By Logical Identities formula, the simplifications and prove is as shown in the attached file.

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RSB [31]

Answer:

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Explanation:

3 0

3 years ago

You recall an algorithm from elementary school for factoring a number N: Divide out all factors of 2, then of 3, then of 4, then

Contact [7]

Answer:

let number = 0

while number < 1

begin

print "Enter a positive integer: "

read number

end

end_while

find and print number's factors:

let prime = TRUE

let currentFactor = 2

let lastFactor = the square root of number truncated

to an integer value

while currentFactor <= lastFactor

begin

if number is evenly divisible by currentFactor

begin

print currentFactor

let number = number / currentFactor

end

else

let currentFactor = currentFactor + 1

end_if

end

end_while

print a message if number is prime:

if prime == TRUE

print "Your number is prime"

end_if

Explanation:

4 0

3 years ago

Which of the following statements is correct?

Reika [66]

Answer:

b. rivets are tempory fasteners that bind two plate of metals together

3 0

3 years ago

A 2 m3 insulated rigid tank contains 3 kg of nitrogen at 90 kPa. Now work is done on the system until the pressure in the tank r

Nutka1998 [239]

Answer: $\Delta S$ = 1.47kJ/K

Explanation: <u>Entropy</u> is the measure of a system's molecular disorder, i.e, the unuseful work a system does.

The nitrogen gas in the insulated tank can be described as an ideal gas, so it can be used the related formulas.

For the entropy, the ratio of initial and final temperatures is needed and as volume is constant, we use:

$\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}$

$\frac{P_{2}}{P_{1}} =\frac{T_{2}}{T_{1}}$

$\frac{T_{2}}{T_{1}} =\frac{175}{90}$

$\frac{T_{2}}{T_{1}} =1.94$

<u>Specific</u> <u>Heat</u> is the quantity of heat required to increase the temperature 1 degree of a unit mass of a substance. Specific heat of nitrogen at constant volume is $c_{v}=$ 0.743kJ/kg.K

The change in entropy is calculated by

$\Delta S= m[c_{v}ln(\frac{T_{2}}{T_{1}})-Rln(\frac{V_{2}}{V_{1}} )]$

For the nitrogen insulated in a rigid tank:

$\Delta S= m[c_{v}ln(\frac{T_{2}}{T_{1}})]$

Substituing:

$\Delta S= 3[0.743ln(1.94)]$

$\Delta S=$ 1.47

The entropy change of nitrogen in an insulated rigid tank is 1.47kJ/K

6 0

3 years ago

How a single force is resolved along the perpendicular axis acting an angle theta with horizontal?

Nataly [62]

Answer:

A single force, which is acting at angle θ from a horizontal axis, can be resolved into components which act along the perpendicular axis.

Consider the perpendicular axis x and y, where x represents the horizontal axis and y represents vertical axis.

The Force is resolved into 2 parts, one acts along x-axis and is represent by X. The other acts along y-axis and is represented by Y.

From the diagram we can see that the Force and its components X and Y makes up a right angles triangle, where θ is the angle from the x-axis

<h3 /><h3>Find X:</h3>

We know that:

cosθ = Base/Hypotenuse

cosθ = X/F

X = Fcosθ

<h3>Find Y:</h3>

We know that:

sinθ = Perpendicular/Hypotenuse

sinθ = Y/F

Y = Fsinθ

<h3>Relation of Force and its Components:</h3>

Force F can be represent by:

F = Fcosθ (along x-axis) + Fsinθ (along y-axis)

As they form a right angled triangle, we can use Pythagoras Theorem to show the relation between Force and its components.

Hypotenuse² = Base² + Perpendicular²

F² = X² + Y²

F² = (Fcosθ)² + (Fsinθ)²

$F = \sqrt{(F\cos\theta)^2+(Fsin\theta)^2}$

Where θ can be found by using any of the trignometric functions.

6 0

3 years ago