Answer:
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Answer:
23.06262m^3/s
Explanation:
The volume flow rate of the water is determined from the needed power output and the elevation difference:
Where, height (h) =221m, power(w)=50MW=50*10^6w
Density of water (ρ)=1000kg/m^3
Efficiency of turbine(η)=100%=1
V=W/ρηgh
=50*10^6m^3/(1)*(1000)*(9.81)*(221)s=23.06262m^3/s
Answer:
t= 9.79 hr
Explanation:
Given that
V= 3.5 V
Capacity= 4 Amp-hour
We know that
V= IR
V= Voltage
I =Current
R=Resistance
V = I R
The total voltage on the batteries will be 2 V
2 x 3.5 = I x 10
I= 0.7 A
We know that Power P
P = V I
P = 0.7 x 7
P =4.9 W
4 A.h and 12 volt power supply = 4 x 12 = 48 W.hr
So time of drain t
4.9 t = 48
t= 9.79 hr
Water vapor and carbon dioxide!
