What friction rate should be used to size a duct for a static pressure drop of 0.1 in wc if the duct has a total equivalent leng
1 answer:
You might be interested in
Answer:
Explanation:
Given
wavelength
distance between two slits
Screen is placed at a distance
Location of a (n+1)th bright fringe is given by
for nth bright fringe
Distance between two bright fringes
Answer:
shrinkae limit = 20.35%
shrinkage ratio = 1.45
Explanation:
1. to get the shrinkage limit we would first calculate the moisture content w.
w = (37-28)/28
= 9/28
= 0.3214
then the formula for shrinkage limit is
w = 0.3214
V = 19.3
Vd = 16
Wd = 28
when we put these values into the formula:
= 20.35%
2. the shrinkage limit = Wd/V
= 28/19.3
= 1.45