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statuscvo [17]
3 years ago
13

Perform unit conversions and determine Re for the case when a fluid with density of 92.8 lbm/ft3 and viscosity of 4.1 cP (centip

oise) flows with a velocity of 237 ft/min in a pipe with 28 inch diameter.
Re = (density*velocity*diameter)/viscosity
Chemistry
1 answer:
erastovalidia [21]3 years ago
4 0

Answer:

Re=309926.13

Explanation:

density=92.8lbm/ft3*(0.45kg/1lbm)*(1ft3/0.028m3)=1491.43kg/m3

viscosity=4.1cP*((1*10-3kg/m*s)/1cP)=0.0041kg/m*s

velocity=237ft/min*(1min/60s)*(0.3048m/1ft)=1.2m/s

diameter=28inch*(0.0254m/1inch)=0.71m

Re=(density*velocity*diameter)/viscosity=(1491.43kg/m3*1.2m/s*0.71m)/0.0041kg/m*s

Re=309926.13

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According to the <u>first law of thermodynamics</u>:

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Substituting values in the above equation:

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