The molar mass of the gas in grams per mole is 27 g/mol
The correct answer to the question is Option D. 27 g/mol
To solve this question, we'll begin by calculating the number of mole of the gas. This can be obtained as follow:
Temperature (T) = 280 K
Pressure (P) = 0.95 atm
Volume (V) = 4.92 L
Gas constant (R) = 0.0821 L⋅atm/mol⋅K
<h3>Number of mole (n) =? </h3>
<h3>PV = nRT </h3>
0.95 × 4.92 = n × 0.0821 × 280
4.674 = n × 22.988
Divide both side by 22.988
n = 4.674 / 22.988
<h3>n = 0.203 mole </h3>
Thus, the number of mole of the gas is 0.203 mole.
Finally, we shall determine the molar mass of the gas. This can be obtained as follow:
Number of mole of gas = 0.203 mole.
Mass of gas = 5.49 g
<h3>Molar mass =? </h3>
Mole = mass / molar mass
0.203 = 5.49 / molar mass
Cross multiply
0.203 × molar mass = 5.49
Divide both side by 0.203
Molar mass = 5.49 / 0.203
<h3>Molar mass = 27 g/mol </h3>
Therefore, the molar mass of the gas is 27 g/mol
Option D. 27 g/mol gives the correct answer to the question.
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