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MakcuM [25]
3 years ago
12

A chemist needs to find out how large of a container would be required to contain the products of an ammonia decomposition. If 8

.91 mol H2 are produced during the reaction, how many moles of N2 are produced?
Chemistry
2 answers:
goldenfox [79]3 years ago
8 0
The answer is 2.97 mol N<span>2</span>
Zielflug [23.3K]3 years ago
3 0

Answer : The moles of N_2 produced are, 2.97 moles

Solution : Given,

Moles of H_2 = 8.91 moles

The balanced decomposition reaction of ammonia will be,

NH_3\rightarrow 3H_2+N_2

From the balanced reaction, we conclude that

When 2 moles of NH_3 decomposes to produce 3 moles of H_2 and 1 mole of N_2

If the moles of H_2 is 3 moles then the moles of N_2 produces = 1 mole

If the moles of H_2 is 8.91 moles then the moles of N_2 produces = \frac{8.91moles}{3moles}=2.97moles

Therefore, the moles of N_2 produced are, 2.97 moles

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Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

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