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aliya0001 [1]
3 years ago
15

A helium balloon has a radius of 2m. The density of helium of helium is 0.17 kg/m3 and the density of air is 1.25 kg/m3. What is

the maximum mass that the balloon can lift?
Physics
1 answer:
3241004551 [841]3 years ago
3 0

To solve this problem we will begin by finding the force on each of the elements. For this it will be necessary to obtain the mass, which can be related to density and volume. Finally, by balancing forces it will be possible to obtain the final value of the maximum mass that can be lifted.

By Newton's second law we have,

F = mg

Here,

g = Gravitational acceleration

m = mass

At the same time mass can be described as,

m_1 = \rho \times V

m_1 = (1.25)\times \frac{4}{3} (2)^2

Therefore the Force 1 is,

F = m_1 g

F = \frac{40\pi }{3} (9.8)

F = 410.501N

Applying the same concepto but for the second mass we have,

m_2 = \rho \times V

m_2 = (0.17) \times \frac{3}{4} \pi 2^2

m_2 = 5.697kg

Now by equilibrium we have,

W + mg = F

m = \frac{F+W}{g}

m = \frac{410.501-55.828}{9.8}

m = 36.19kg

Therefore the maximum mass lift by balloon is 36.19kg

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3241004551 [841]

Answer:T=12.69^{\circ}C

Explanation:

Given

Mass of ice m=60 gm

mass of water M=760 gm

Initial Temperature of water T_i=20^{\circ}C

Let T be the Final Temperature of mixture

Latent heat of Fusion L=334 J/gm

heat required to melt ice completely is

Q_1=60\times 334=20.04 kJ

Heat released by water is taken by ice thus

Mc_{water}(20-T)=mL+mc_{water}(T-0)

0.76\times 4.184\cdot (20-T)=20.04+0.06\times 4.184\cdot (T)

T=12.69^{\circ}C

                       

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Explanation:

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A parallel-plate capacitor is constructed from two 6.0 cm × 6.0 cm electrodes spaced 1.5 mmapart. The capacitor plates are charg
Brilliant_brown [7]

A) 2.4\cdot 10^{-6} J

The energy stored in a capacitor is given by:

E=\frac{1}{2}\frac{Q^2}{C}

where

Q is the charge stored

C is the capacitance

The capacitance of a parallel-plate capacitor is

C=\frac{\epsilon_0 A}{d}

where

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

A=6.0 cm \cdot 6.0 cm=36.0 cm^2=36\cdot 10^{-4} m^2 is the area of each plate

d=1.5 mm=0.0015 m is the distance between the plates

Substituting,

C=\frac{(8.85\cdot 10^{-12} F/m)(36\cdot 10^{-4} m^2)}{0.0015 m}=2.1\cdot 10^{-11} F

The charge stored on the capacitor is

Q=10 nC=10\cdot 10^{-9}C

So, the energy stored is

E=\frac{1}{2}\frac{(10\cdot 10^{-9}C)^2}{2.1\cdot 10^{-11} F}=2.4\cdot 10^{-6}J

B) 2.6\cdot 10^{-6}J

This time, the separation between the plates is

d = 1.7 mm = 0.0017 m

So, the new capacitance is

C=\frac{(8.85\cdot 10^{-12} F/m)(36\cdot 10^{-4} m^2)}{0.0017 m}=1.9\cdot 10^{-11} F

And so, the new energy stored is

E=\frac{1}{2}\frac{(10\cdot 10^{-9}C)^2}{1.9\cdot 10^{-11} F}=2.6\cdot 10^{-6}J

C)

Energy must be conserved, so the difference between the initial energy of the capacitor and its final energy is just equal to the work done to increase the separation between the two plates from 1.5 mm to 1.7 mm (in fact, the two plates of the capacitor attract each other since they have opposite charge, so work must be done in order to increase their separation)

7 0
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Objects tend to stay moving because of a force called inertia.<br><br> True or False?
kifflom [539]
True I think because if you search in google it says that object that tend to move is because of inertia
7 0
3 years ago
Read 2 more answers
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