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Nookie1986 [14]
3 years ago
7

The isotope Np-238 has a half life of 2.0 days if 96 grams of it were present on Monday how much will remain six days later

Chemistry
1 answer:
Neporo4naja [7]3 years ago
4 0

Answer:

12 grams

Explanation:

For any radioactive substance

the amount of substance left after n half life  is given by = x/2^n

where x the original amount of substance.

____________________________________________

Half life of isotope Np-238 = 2 days

total no of days = 6

no of half life =total no of days/Half life of isotope Np-238 = 6/2 = 3

thus,

for our problem n = 3

initial amount of Np-238 = 96 grams

thus,

the amount of substance left after 3 half life = 96/2^3 = 96/8 = 12 grams.

Thus, 12 grams will be left after six days.

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Answer:
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Explanation:
One mole of any substance contains Avogadro's number (6.022 * 10^23) of atoms. 
Therefore, to know the number of moles that contain 3.85 * 10^24 atoms, all we have to do is cross multiplication as follows:
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number of moles = (3.85 * 10^24 *1) / (6.022 * 10^23)
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Hope this helps :)
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