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Nookie1986 [14]
3 years ago
7

The isotope Np-238 has a half life of 2.0 days if 96 grams of it were present on Monday how much will remain six days later

Chemistry
1 answer:
Neporo4naja [7]3 years ago
4 0

Answer:

12 grams

Explanation:

For any radioactive substance

the amount of substance left after n half life  is given by = x/2^n

where x the original amount of substance.

____________________________________________

Half life of isotope Np-238 = 2 days

total no of days = 6

no of half life =total no of days/Half life of isotope Np-238 = 6/2 = 3

thus,

for our problem n = 3

initial amount of Np-238 = 96 grams

thus,

the amount of substance left after 3 half life = 96/2^3 = 96/8 = 12 grams.

Thus, 12 grams will be left after six days.

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V = 1000 cm^3

0.10 = M / 1000
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4 0
3 years ago
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MrRissso [65]

Answer:

Explanation:

From the given information:

TO start with the molarity of the solution:

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\Delta \ T_f = 2.9 ^0 \ C

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K_f = 4.82 ^0 C / m}

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= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ NH_4Cl}{53.5 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

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i = \dfrac{7.3 \ ^0 \ C}{4.82 ^0 \ C/m \times 1.00 \ m}

\mathbf {i = 1.51 }

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mezya [45]

Answer:

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Explanation:

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