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Ghella [55]
2 years ago
10

Which of the following best represents both accuracy and precision

Chemistry
2 answers:
liq [111]2 years ago
6 0

Answer: Measurement B

Explanation:

Precision refers to the closeness of two or more measurements to each other.

For Example: If we measure a length three times and we get 3.5 m each time. Then the measurement is very precise.

Accuracy refers to the closeness of a measured value to a standard or known value.

For Example: If the length of the substance is 4 m and one person measures 3.9 m and another person measures 3.8 m. Then, the length measured by first person is more accurate.

Thus measurement B represents both accuracy as well as precision as the darts are close and pointed at the center.

makkiz [27]2 years ago
5 0
Accuracy is when you hit as close as to the target as you can and precision is when you are on point
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Draw the product that valine forms when it reacts with excess CH3CH2OH and HCl followed by a wash with aqueous base.
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Answer:

Product: ethyl L-valinate

Explanation:

If we want to understand what it is the molecule produced we have to an<u>alyze the reagents</u>. We have valine an <u>amino acid</u>, in this kind of compounds we have an <em>amine group</em> (NH_2) and a <em>carboxylic acid</em> group (COOH).  Additionally, we have an <u>alcohol </u>(CH_3CH_2OH) in the presence of HCl (a <u>strong acid</u>) in the first step, and a base (OH^-).

When we have an acid and an alcohol in a vessel we will have an <u>esterification reaction</u>. In other words, an ester is produced. As the <em>first step,</em> the oxygen in the C=O (in the carboxylic acid group) would be protonated. In the <em>second step</em>, the ethanol attacks the carbon in the C=O of the carboxylic acid group producing a new bond between the oxygen in the ethanol and the carbon in the carboxylic acid. In <em>step 3</em>, a proton is transferred to produce a better leaving group (H_2O). In <em>step 4</em>, a water molecule leaves the main structure to produce again the double bond C=O. <em>Finally</em>, a base (OH^-) removes the hydrogen from the C=O bond to produce ethyl L-valinate

See figure 1

I hope it helps!

7 0
3 years ago
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4 0
3 years ago
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Answer:

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Explanation:

Hello there!

In this case, since the vaporization process is carried out in order to turn a liquid into a gas due to the addition of heat, we can use the following heat equation involving the heat of vaporization of water or any other substance:

Q=m*\Delta _{vap}H

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Regards!

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