_h2o2(aq)-_h2o(l) +o2(g)
1 answer:
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The intensity of the magnetic force exerted on the wire due to the presence of the magnetic field is given by
where
I is the current in the wire
L is the length of the wire
B is the magnetic field intensity
is the angle between the direction of the wire and the magnetic field
In our problem, L=65 cm=0.65 m, I=0.35 A and B=1.24 T. The force on the wire is F=0.26 N, therefore we can rearrange the equation to find the sine of the angle:
and so, the angle is
where
I is the current in the wire
L is the length of the wire
B is the magnetic field intensity
In our problem, L=65 cm=0.65 m, I=0.35 A and B=1.24 T. The force on the wire is F=0.26 N, therefore we can rearrange the equation to find the sine of the angle:
and so, the angle is
Answer:
the kinetic energy lost due to friction is 22.5 J
Explanation:
Given;
mass of the block, m = 0.2 kg
initial velocity of the block, u = 25 m/s
final velocity of the block, v = 20 m/s
The kinetic energy lost due to friction is calculated as;
Therefore, the kinetic energy lost due to friction is 22.5 J