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s344n2d4d5 [400]
3 years ago
14

A space station, in the form of a wheel 140 m in diameter, rotates to provide an "artificial gravity" of 3.90 m/s2 for persons w

ho walk around on the inner wall of the outer rim. find the rate of rotation of the wheel (in revolutions per minute) that will produce this effect.
Physics
1 answer:
Zigmanuir [339]3 years ago
8 0
Radial acceleration is given by

a_{rad}= \frac{v^2}{r}
where 

v=r \omega
then

a_{rad}= \frac{r^2 \omega^2}{r}=r\omega^2

Now

70\omega^2=3.90 \frac{m}{s^2}  \\  \\ \omega= \sqrt{ \frac{3.9}{70} }

Using the relation

\omega=2 \pi f

2 \pi f= \sqrt{ \frac{3.9}{70} }\\  \\ f= \frac{1}{2 \pi}\sqrt{ \frac{3.9}{70} }Hz

Putting into rpm

\frac{60}{2 \pi}\sqrt{ \frac{3.9}{70}} =2.254rpm

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Force F=2.0N i - 3.0N k acts on a pebble with position vectorr=0.50m j - 2.0m k relative to the origin. In unit vector notation,
klasskru [66]

Answer with Explanation:

We are given that

Force acts on a pebble=2\hat{i}-3\hat{k} N

Position vector=r=0.5\hat{j}-2\hat{k} m

a.We have to find the resulting torque on the pebble about origin.

Torque=r\times F

Substitute the values then we get

Torque= (0.5j-2k)\times (2i-3k)

Torque=-k-1.5i-4jN-m

By using i\times j=k,j\times k=i,k\times i=j,j\times i=-k,k\times j=-i,i\times k=-j,i\times i=j\times j=k\times k=0

b.r=2i-3k

r-r_1=(0.5j-2k)-(2i-3k)=-2i+0.5j+k

Torque about point (2,0,-3)

\tau=(-2i+0.5j+k)\times (2i-3k)

\tau=-6j-k-1.5i+2j=-1.5i-4j-kN-m

6 0
3 years ago
Back<br> 8<br> 8.<br> 9.<br> 10.<br> 11.<br> 12.<br> 13.<br> 13
deff fn [24]

Answer:

i dont know the answer for this question sorry for the misunderstanding

Explanation:

3 0
3 years ago
En una fundición hay un horno eléctrico con capacidad para fundir totalmente 540 kg de cobre. Si la temperatura inicial del cobr
11Alexandr11 [23.1K]

Answer:

Q = 2.95*10^5 kJ

Explanation:

In order to calculate the energy required to melt the cooper, you first calculate the energy required to reach the boiling temperature. You use the following formula:

Q_1=mc(T_b-T_1)     (1)

m: mass of cooper = 540 kg

c: specific heat of cooper = 390 J/kg°C

Tb: boiling temperature of cooper = 1080°C

T1: initial temperature of cooper = 20°C

You replace the values of the parameters in the equation (1):

Q_1=(540kg)(390\frac{J}{kg.\°C})(1080\°C-20\°C)=2.23*10^8J

Next, you calculate the energy required to melt the cooper by using the following formula:

Q_2=mL_f         (2)

Lf: melting constant of cooper = 134000J/kg

Q_2=(540kg)(134000\frac{J}{kg})=7.24*10^7J

Finally, the total amount of energy required to melt the cooper from a temperature of 20°C is the sum of Q1 and Q2:

Q=Q_1+Q_2=2.23*10^8J+7.24*10^7J=2.95*10^8J=2.95*10^5kJ

The total energy required is 2.95*10^5 kJ

3 0
3 years ago
Please answer this question ​
belka [17]

ANSWER is c

HOPR THIS WILL BE HELPFUL

8 0
3 years ago
Where does wave reflection occur?
alisha [4.7K]
Wave reflection occurs when waves reflect or rebound off of a surface. This is like an echo because the sound waves are reflected from a distant surface 
7 0
3 years ago
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