Answer: Speeding up the orbital speed of earth so it escapes the sun require the greater energy.
Explanation: To find the answer, we need to know more about the Orbital and escape velocities.
<h3>
What is Orbital and Escape velocity?</h3>
- Orbital velocity can be defined as the minimum velocity required to put the satellite in its orbit around the earth.
- The expression for orbital velocity near to the surface of earth will be,

- Escape velocity can be defined as the minimum velocity with which a body must be projected from the surface of earth, so that it escapes from the gravitational field of earth.
- The expression for orbital velocity will be,

- If we want to get into the sun, we want to slow down almost completely, so that your speed relative to the sun became almost zero.
- We need about twice the raw speed to go to the sun than to leave the sun.
Thus, we can conclude that, the speeding up the orbital speed of earth so it escapes the sun require the greater energy.
Learn more about orbital and escape velocity here:
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1) Inversely
2) increases
3) Boyle's
4) mass
5) Kelvin
6) Charles's
7) Gay-Lussac's
8) directly
9) combined
10) the amount
<span>The pressure and volume of a fixed mass of gas are inversely related. If one decreases, the other increases. This relationship is known as Boyle's law. The volume of a fixed mass of a gas is directly proportional to its kelvin temperature. This relationship is known as Charles's law. Gay-Lussac's law states that the pressure of a gas is directly proportional to the kelvin temperature if the volume remains constant. These three separate gas laws can be written as a single expression called the combined gas law. It can be used in situations in which only the amount of gas is constant. </span>
Answer: try searching It up on go0gle
Explanation:
The coefficient of static friction is 0.222
Explanation:
In order for the car to remain in circular motion, the frictional force must be able to provide the necessary centripetal force. Therefore, the car will start skidding when the two forces are equal:

where the term on the left is the frictional force, while the term on the right is the centripetal force, and where
is the coefficient of static friction
m is the mass of the car
g is the acceleration of gravity
v is the speed of the car
r is the radius of the track
In this problem, we have:
r = 564 m
v = 35 m/s

And re-arranging the equation for
, we can find the coefficient of static friction:

Learn more about friction:
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