Answer:
LolnnrjejahaushanakKababab
Explanation:
Source: Trust me bro
Answer:
The correct option is;
S is more nucleophiclic than O because S is larger than O therefore S is less well solvated than O
Explanation:
Here we have
As the size of atoms increases, the basicity increases and the nucleophilicity increases. Therefore since S is larger than O it is more nucleophilic than O.
Also we have smaller nucleophiles are more solvated than larger nucleophiles therefore S is less well solvated than O.
Which gives the correct answer as;
S is more nucleophiclic than O because S is larger than O therefore S is less well solvated than O.
To make it easier, assume that we have a total of 100 g of a compound. Hence, we have 58.80g of xenon, 7.166g of oxygen, and 34.04g of fluorine.
Know we will convert each of these masses to moles by using the atomic masses:
58.8/131.3 = 0.45 mole of Xe
7.166/16 = 0.45 mole of O
34.04/19 = 1.79 mole of F
Now, we will divide all the mole numbers by the smallest among them and get the number of atoms in the compound:
Xe = 0.45/0.45 = 1
O = 045/0.45 = 1
F = 1.79/0.45 = 3.98 = 4
So, the empirical formula of the compound XeOF₄
The molecular formula:
The molecular formula is N₂O₄.