Question

A fixed amount of oxygen gas is held in a .500 L tank at a pressure of 4.39 atm. The tank is connected to an empty 1.50 L tank by a tube with a valve. After this valve has been opened and the oxygen is allowed to flow freely between the two tanks at a constant temperature, what is the final pressure in the system?

Answer 1

Answer:

1.0975 atm.

Explanation:

According to Boyle’s Law: " At constant temperature , the  volume of a given quantity of a gas  varies inversely with its pressure".

P α 1/V.

∴ P₁V₁ = P₂V₂.

P₁ = 4.39 atm, V₁ = 0.5 L.

P₂ = ??? atm, V₂ = 2.0 L.

∴ P₂ = P₁V₁/V₂ = (4.39 atm)(0.5 L) / (2.0 L) = 1.0975 atm.