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2 years ago

LolnnrjejahaushanakKababab

Chemistry

1 answer:

snow_lady [41]2 years ago

4 0

Answer:

LolnnrjejahaushanakKababab

Explanation:

Source: Trust me bro

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How many moles of AI are necessary to produce 5.92 miles of hydrogen gas

telo118 [61]

Answer:

Explanation:

why I needed to give a answer to a question. I want to ask the question. brainly solve this issue. i cant ask questions without answering to 1 questions.

8 0

2 years ago

The rate constant for a certain reaction is k = 5.40×10−3 s−1 . If the initial reactant concentration was 0.100 M, what will the

IceJOKER [234]

Answer : The concentration after 17.0 minutes will be, $4.05\times 10^{-4}M$

Explanation :

The expression for first order reaction is:

$[C_t]=[C_o]e^{-kt}$

where,

$[C_t]$ = concentration at time 't' (final) = ?

$[C_o]$ = concentration at time '0' (initial) = 0.100 M

k = rate constant = $5.40\times 10^{-3}s^{-1}$

t = time = 17.0 min = 1020 s (1 min = 60 s)

Now put all the given values in the above expression, we get:

$[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}$

$[C_t]=4.05\times 10^{-4}M$

Thus, the concentration after 17.0 minutes will be, $4.05\times 10^{-4}M$

4 0

2 years ago

after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 2

Alexxandr [17]

Molar concentration = (numbet of mol Solute)/ ( volume Solution)

1) Finding
the number of the mol solute

$22.0 g AgNO3 * \frac{1 mol AgNO3}{169.91 g AgNO3} = 0.129 mol AgNO3

2) 725 ml = 0.725 L


$

$3) Molarity = \frac{number/ mol/solute}{Volume/solution} = \frac{0.129}{0.725} 

$

$Molarity= \frac{0.178 mol}{L} , 

or 0.178 M
$

3 0

3 years ago

1) How many moles are in 4.0x10^24 atoms?

-Dominant- [34]

Answer:

<h2>6.64 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{4 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 6.644518...$

We have the final answer as

<h3>6.64 moles</h3>

Hope this helps you

3 0

3 years ago

Сгорело 6 г угля С. Вычислите массу образовавшегося оксида углерода (IV)<br>просто скажите ответ

skad [1K]

English<span>Сгорело 6 г угля С. Вычислите массу образовавшегося оксида углерода (IV)
просто скажите ответ</span>

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3 years ago