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jeka57 [31]
3 years ago
13

LolnnrjejahaushanakKababab

Chemistry
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

LolnnrjejahaushanakKababab

Explanation:

Source: Trust me bro

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Explanation:

It is known that,

      Molar mass of Cd = 112.41 g/mol

Standard concentration of Cd = 0.005 mg/L = 0.005 \times 10^{-3} g/L

Hence, we will calculate the molarity as follows.

        Molarity = \frac{0.005 \times 10^{-3}}{112.41} mol/L

                       = 4.45 \times 10^{-8} M

Equation for the reaction is as follows.

          Cd(OH)_{2} \rightleftharpoons Cd^{2+} + 2OH^{-}

         K_{sp} = [Cd^{2+}][OH^{-}]^{2}]

          2 \times 10^{-34} = 4.45 \times 10^{-8} \times [OH^{-}]^{2}

          [OH^{-}] = 6.7 \times 10^{-4} M

Also,

         [H^{+}] = \frac{10^{-14}}{[OH^{-}]}

                      = \frac{10^{-14}}{6.7 \times 10^{-4}}

                      = 1.49 \times 10^{-11} M

Relation between pH and concentration of hydrogen ions is as follows.

               pH = -log [H^{+}]

                     = -log (1.49 \times 10^{-11} M)

                     = 10.82

Thus, we can conclude that a minimum pH of 10.82 is necessary to reduce the dissolved cadmium ion concentration to the standard.

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